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using ceil and floor

Pages: 12
Nov 12, 2011 at 12:07am
Moschops (7244)
You've got lost in the logic. Your code above says:

First, check to see if percentage is the same as 85, and THEN, if it is, floor it.

Do you see how that's completely back to front?

You need to floor it first, and THEN check to see if the new value is the same as 85.
Last edited on Nov 12, 2011 at 12:07am
Nov 12, 2011 at 12:16am
psp1202 (28)
When I do it this way it still doesnt work
Last edited on Nov 12, 2011 at 12:34am
Nov 12, 2011 at 12:21am
Moschops (7244)


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#include <iostream>
#include <cmath>

using std::cout;
using std::endl;
int main()
{
  double percentage;
 
  std::cout << "Enter percentage (e.g. 58.974)" << std::endl;
  std::cin >> percentage;

  percentage = floor(percentage);


if (percentage >= 95)
	{
		cout << "You got an A" << endl;
	}
	else if (percentage >= 90 && percentage < 95)
	{
		cout << "You got a A-" << endl;
	}
	else if (percentage > (85) && percentage < 90)
	{
		cout << "You got a B+" << endl;
	}
	else if (percentage == 85)
	{
		cout << "You got a B" << endl;
	}
	else if (percentage >= 80 && percentage < 85)
	{
		cout << "You got a B-" << endl;
	}
	else if (percentage > 75 && percentage < 80)
	{
		cout << "You got a C+" << endl;
	}
	else if (percentage == 75)
	{
		cout << "You got a C" << endl;
	}
	else if (percentage >= 70 && percentage < 75)
	{
		cout << "You got a C-" << endl;
	}
	else if (percentage > 65 && percentage < 70)
	{
		cout << "You got a D+" << endl;
	}
	else if (percentage == 65)
	{
		cout << "You got a D" << endl;
	}
	else if (percentage >= 60 && percentage < 65)
	{
		cout << "You got a D-" << endl;
	}
	else
	{
		cout << "You got a F" << endl;
	}

 return 0;
}
Edit & run on cpp.sh
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Pages: 12