Functions

[cozyhozy]

Does anyone know what is these codes trying to do?
And what are the mistakes in it?


#include<stdio.h>

int f(int x, int y);

int main()
{
int x, y, results;
x=3;
y=4;
results=f(x,y);
x=f(y, result+x);
y=f(1, f(results,2) );
return 0;
}

int f( int x, int y)
{
return x*x + y*y;
}

[eng soso]

just put the letter "s" to the word results>>>x=f(y, result+x);

& u will have no error

[cozyhozy]

hi thanks.
can i know what is this codes trying to do?
and there is no output?

[eng soso]

it's a simple example of funcs

there's no output coz there's no cout operation

try to put -

printf("%d",x); for example

[InterFiction]

This code includes header file.
#include<stdio.h>

http://pubs.opengroup.org/onlinepubs/7908799/xsh/stdio.h.html

int main()
{
int x, y, results;
x=3;
y=4;
results=f(x,y);
x=f(y, result+x);
y=f(1, f(results,2) );
return 0;
} 

this is your main function.

[InterFiction]

reply, I just realized I missed a lot of code in there. I'm going to edit some of that out, and just leave in what I know is right, so you don't get messed up.

[InterFiction]

I wanted to take another crack at it, but being a newb it's hard for me to decipher. I know someone that could do it, if they could find the time, and had the patience ;).

here's my second take.

#include<stdio.h>

includes header file

int f(int x, int y);

this to me looks like the declaration of a function, but I'm not sure. It looks weird because because it doesn't have a body of code to run between curly brackets. Someone with more experience is going to have to touch on that one.

int x, y, results;
x=3;
y=4;
results=f(x,y);

declares variables x,y, and results
it gives x the value of 3, y the value of 4, and results the value of called function f.

x=f(y, result+x);

this gives x the value of called function f after it calculates.



y=f(1, f(results,2) );

this gives y the value of called function f after it calculates with passed arguments 1, f(results,2)

return 0;

this is the functions return value. 0 is usually used for void functions, as far as I know.

}

int f( int x, int y)
{
return x*x + y*y;
}

to me this looks like the declaration of function f.
it returns the value of x times x plus y times y.

the order of precedence is

brackets, exponents, dividing, multiplying, adding, and subtracting.

sense there's only multiplying, and adding. it would multiply first, and then add.

so answer for x time x would be added to the answer of y times y...

what this program does I have no idea...but I can tell you by the looks of it it doesn't do much useful, lol.

[InterFiction]

there's no user input for anything, so I'm thinking, if it runs at all...it just calculates based on some computer stuff, plus what variables are given values.

[cozyhozy]

Thank you for taking your time to explain!
Yup i guess this program is just a sample and not much of use. Haha
Thanks once again :)