C++ Pass by reference/value.....???

[Julianne]

Hi, I have an assignment where I have to have the user input 2 values, x and y, switch the two values, then raise x to the y power. I have to use pass by value in one and pass by reference in another. This is the code I have so far for pass by reference and it works, but I don't know how to use pass by value...

Thanks!
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#include <stdio.h>
#include <iostream.h>
#include <math.h>

void swapnum(int &T, int &S) {
int temp = T;
T = S;
S = temp;


}

int main(void) {

int a, b ;

cout << "This will take your entered values for a and b then switch"
"\n the values and perform A^B.\n"<< endl;
cout << "\n Please enter the value for A \n" << endl;
cin >> a;
cout << "\n Please enter the value for B \n" << endl;
cin >> b;


swapnum(a, b);
cout <<" \n The value for A is now = "<< a <<"\n \n The value for B is now = "
<< b <<endl;

cout << "\n The program will now take A^B and have a value of " << pow (a,b)
<< " \n " <<endl;

system ("pause");

return 0;
}

[network burner]

your function swapnum returns nothing to the main function. Hence the values in the main function arent interchanged at all...
either use references or COUT inside the swapnum function

[Cuddlebuddie928]

@ Julianne: You are passing by reference with the use of the '&' in front of each parameter name.

pass by reference: void swapnum(int &T, int &S) //ok

pass by value: void swapnum(int T, int S) //this would not work


@ network burner: Julianne's already passing by reference... the function should work.