Program with switch and sentinel loop
Hello,
A beginner hoping someone could point me in the right direction with regards to this program. I'm getting confused when working with a sentinel loop. This is homework for me, so that is why I'm not looking for someone to give me the complete solution.
This is what I currently have. Thank you for whatever help you may give
#include <iostream>
#include <iomanip>
using namespace std;
const int q = -1;
int main ()
{
char option = ' ';
float volume, area, girth, length, width, depth;
cout << "To determine Volume, enter V \n"
<< "To determine Surface Area, enter A \n"
<< "To determine Girth, enter G \n"
<< "To quit, enter Q\n";
cin >> option;
cout << "Please input the length: ";
cin >> length;
cout << "Please input the width: ";
cin >> width;
cout << "Please input the depth: ";
cin >> depth;
while (option != q)
{
switch (option)
{
case 'V':
volume = length * width * depth;
cout << "The volume of the object is: " << volume << endl;
break;
case 'A':
area = 2 *(length * width) + 2 *(width * depth) + 2 *(length * depth);
cout << "The surface area of the object is: " << area << endl;
break;
case 'G':
girth = 2 * (length + width) + depth;
cout << "The girth of the object is: " << girth << endl;
break;
}
system("pause");
return 0;
}
A beginner hoping someone could point me in the right direction with regards to this program. I'm getting confused when working with a sentinel loop. This is homework for me, so that is why I'm not looking for someone to give me the complete solution.
This is what I currently have. Thank you for whatever help you may give
#include <iostream>
#include <iomanip>
using namespace std;
const int q = -1;
int main ()
{
char option = ' ';
float volume, area, girth, length, width, depth;
cout << "To determine Volume, enter V \n"
<< "To determine Surface Area, enter A \n"
<< "To determine Girth, enter G \n"
<< "To quit, enter Q\n";
cin >> option;
cout << "Please input the length: ";
cin >> length;
cout << "Please input the width: ";
cin >> width;
cout << "Please input the depth: ";
cin >> depth;
while (option != q)
{
switch (option)
{
case 'V':
volume = length * width * depth;
cout << "The volume of the object is: " << volume << endl;
break;
case 'A':
area = 2 *(length * width) + 2 *(width * depth) + 2 *(length * depth);
cout << "The surface area of the object is: " << area << endl;
break;
case 'G':
girth = 2 * (length + width) + depth;
cout << "The girth of the object is: " << girth << endl;
break;
}
system("pause");
return 0;
}
Should you fix it like below?
from:
const int q = -1;
to:
const char q = 'Q';
move:
while (option != q)
{
right after:
float volume, area, girth, length, width, depth;
from:
const int q = -1;
to:
const char q = 'Q';
move:
while (option != q)
{
right after:
float volume, area, girth, length, width, depth;
closed account (zb0S216C)
| Yooper wrote: |
|---|
| This is homework for me, so that is why I'm not looking for someone to give me the complete solution. (sic) |
Finally! Only if all newcomers were like you.
I've noticed something here. The while loop is set to continue while option has a value other than negative one; that's fine. However, option is never given the chance to change its value, via std::cin. Without input, the while loop will never be false, thus, the loop will forever continue. Place a std::cin statement within the while loop and place the given value within option. I'll let you decide where in the loop the statement should go.
Wazzak
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