Lvalue required as left operand of assignment

[Mas15]

I got the error mentioned in the title on this line of code.
number%divisor=final;
In this code

#include <iostream>

int main (int argc, char * const argv[]) {
	int number=0, divisor=0, final;
	std::cout<<"Please enter a number\n";
	std::cin>>number;
	while (divisor<number){
		divisor=+1;
		number%divisor=final;
		if (final==0){
			std::cout<<divisor<<"\n";
		}
	}
	std::cout<<"done\n";
    return 0;
}

Ideas?

[Disch]

2 problems that I spot:

divisor=+1;

This is assigning divisor to 1. IE, it's the same as this:

divisor = +1;  // assign positive 1 to divisor 

If you want to increment divisor by one, you want to use +=:

divisor += 1;

Furthermore:

number%divisor=final;

you have this backwards. The variable being assigned needs to be on the left side of the = operator.

final = number % divisor;  // assigns the result of (number % divisor) to final 

[Mas15]

Thanks it works perfectly. I can't believe I was stupid enough to make those mistakes, haha.