Rounding Minutes up to nearest Hour.

[mbentley1989]

Hi guys. I'm currently taking Beginning Visual Basic programming class.
I'm doing my 3rd project but I am completely stuck and cannot continue.

I am doing a project where I have to program a bill generator and I have to include a rate and time expressed in minutes. I kind of understand rounding at least rounding up to the nearest whole number, but I have to round minutes up to the nearest number.

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
	// 1.0 Input
	cout << "Marlene's Outfit Rental Calculator" << endl << endl;
	cout << "Please enter the following values:\n" << endl;

	// 1.1 MINUTES RENTED
	float rentalMinutes;
	cout << "Total Rental Minutes\t-> ";
	cin >> rentalMinutes;
	//. stuck here
	if((rentalMinutes + 0.5) >= (int(rentalMinutes)+1));
	cout << rentalMinutes << " rounds to " << int(rentalMinutes)+1 << endl;
        // I don't even know what I am doing here.
	cout.setf(ios::showpoint);
	cout.setf(ios::fixed);
	cout.precision(60);
	getch();
}
	

For example, if I was to input 61 I am supposed to round it up to the next hour, 120 minutes. Or, if it was 50 minutes I'm supposed to round it to 60.
I can round 61 to 62, but I can get it to round to 120.

Any help would be greatly appreciated guys.

Oh, and this isn't my entire code, I just posted what I am truly having trouble with, the other stuff I can manage. (kinda :P)

[webJose]

If the modulus of rentalMinutes divided by 60 is greater than zero, then add 60 minutes to the result of the integer division between rentalMinutes and 60.

[ascii]

Hi guys. I'm currently taking Beginning Visual Basic programming class.

It's usually good for a course to know what the course is... this is C++

Every hour is a multiple of 60, so if 60 is not evenly divisible into a number, it needs to be rounded up. Just increment the number to a multiple of 60 by adding hours % number to number/
EDIT: Damn, already posted while I was typing :(

[mbentley1989]

I still don't get it, I'm sorry I'm stupid.

This is how I'm doing it.

	// 1.1 MINUTES RENTED
	float rentalMinutes;
	cout << "Total Rental Minutes\t-> ";
	cin >> rentalMinutes;
	//. stuck here
	if((rentalMinutes / 60) > 0);
	{ 
	rentalMinutes/60 + 60;
	}

Edit: ascii, I'm taking com120

[webJose]

Your if is wrong. Your if reads: "If the integer division between rentalMinutes and 60 is greater than zero". But it has to read: "If the modulus of the integer division between rentalMinutes and 60 is greater than zero".

[mbentley1989]

This is my entire code. It's still work in progress, I tried defining an hour by dividing realMinutes by 60. I got over that one hurdle; It works sofar, but I'm still working on it.

I would have liked to have learned to use modulus, but I just didn't get it.

Disregard all the extra symbols, it's there for cosmetic features.

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
	// 1.0 Input
	cout << "Marlene's Cosplay Outfit Rental Calculator!!!" << endl << endl;
	cout << "Please enter the following values:\n" << endl;

	// 1.1 MINUTES RENTED
	float rentalMinutes;
	cout << "Total Rental Minutes\t-> ";
	cin >> rentalMinutes;
	//. stuck here
	int hours = (rentalMinutes + 59)/60;
	
	if ( !cin )
	{
		// reset input for pause
		cin.clear();
		cin.ignore();

		// report and quit
		cout << "Non-numeric input: Program closing" << endl;
		cout << endl << "Press ENTER to finish...";
		cin.ignore(99,'\n');
		return 1;
	}
	cin.ignore(99,'\n');

	// 1.2 RENTAL RATE
	float rentalRate;
	cout << "Hourly Rental Rate\t-> ";
	cin >> rentalRate;
	if ( !cin )
	{
		cin.clear();
		cin.ignore();

		cout << "Non-numeric input: Program terminating" << endl;
		cout << endl << "Press ENTER to finish...";
		cin.ignore(99,'\n');
		return 1;
	}
	cin.ignore(99,'\n');

	// 1.3 RENTAL FEE
	int flatRentalFee;
	cout << "Enter Rental Fee\t-> ";
	cin >> flatRentalFee;
	if ( !cin )
	{
		cin.clear();
		cin.ignore();

		cout << "Non-numeric input: Program terminating" << endl;
		cout << endl << "Press ENTER to finish...";
		cin.ignore(99,'\n');
		return 1;
	}
	cin.ignore(99,'\n');

	// Calculate Rental Costs
	float totalRentalCost = rentalRate * hours;
	float serviceTax = totalRentalCost * 0.04;
	float totalBill = totalRentalCost + flatRentalFee + serviceTax;
	if ( rentalMinutes >= 1 )
	{

	}

	// 3 OUTPUT (EXTRA SPACING AND SYNTAX FOR APPEARANCE)
	cout << "\n==============================================================" << endl;
	cout << "Rental Bill" << endl << endl;

	cout << "Costume Rental Fee: $		" << flatRentalFee << endl;
	cout << "Total Rental Cost:		" << totalRentalCost << endl;
	cout << "Service Tax:\t\t\t" << serviceTax << endl;
	cout << "			    ----------" << endl;
	cout << "Total Bill:\t    $" << endl << endl << endl;

	// 4 FINISH
	cout << "Programmed by Marlene Bentley" << endl;
	cout << "Press ENTER to exit..." << endl;

	getch();
}

Anyway thank you. :)
Edit: more coder-friendly

[coder777]

Please use [code][/code] instead of [quote][/quote]

This int hours = (rentalMinutes + 59)/60; is not the correct rounding. To get the nearest hour write int hours = (rentalMinutes + 30)/60;

Modulus is 'rest of': 16 % 10 = 6 while integer devision is 16 / 10 = 1

[mbentley1989]

To get the nearest hour write int hours = (rentalMinutes + 30)/60;

You're right, this would round 64 minutes down to 60, but I am trying to round up to 120, 2 hours. Sorry, if I wasn't clear. ^^;