Error in File Management Section while find and replace function

[somshridhar]

Dear Sir,

I am just briefing my program to you

The program basic is like I have one input file inpt.txt
Shri
600001
600003
Proactive
600004
600006

First I am reading this input file. Now I have other input1.txt file as

600001
I went to college
600002
I don't go to college.
It is tedious program
6000003
Shridhar Ram Rahim
6000004
Very Easy Program
6000005
Life is nice
6000006


Now I want to take input from input.txt use it in input1.txt and produce the output.txt file as foloows:

600001:shri
I went to college
600002:shri
I don't go to college.
It is tedious program
6000003:shri
Shridhar Ram Rahim
6000004:Proactive
Very Easy Program
6000005:Proactive
Life is nice
6000006:Proactive


Please help me as I could able to produce output.txt fie but I could not repeat it for other numbers
Thank you
EditReport

brokenbot (248) Aug 26, 2011 at 1:19pm
Show more code... explain your problem better.

You want to take inpt.txt data and input1.txt data and mash data together and make a new file called output.txt. I don't really understand your system of how you're going to actually know where to put data from inpt.txt and input1.txt to actually logically come up with output.txt

I thought for a second that shri.... ok I get it now. Your numbers are messed up in inpt.txt though.

I don't get how your generating these magical numbers.... Why do you need them?

Do you want to parse a file for a number then match that number in another file resulting in modified output that goes in a completely different file?
Last edited on Aug 26, 2011 at 1:25pmReport

somshridhar (6) Aug 29, 2011 at 12:06pm
Dear Sir,

As per your wish I am just giving my code to you.

My input.txt

Enter_the_number_of_names
2
Enter_the_name
Enter_the_range_of_points
Shri
600001
600003
Proactive
600004
600006



My input1.txt

$POINT ID = 600001
I went to college
$POINT ID = 600002
I don't go to college.
It is tedious program
$POINT ID = 6000003
Shridhar Ram Rahim
$POINT ID = 6000004
Very Easy Program
$POINT ID = 6000005
Life is nice
$POINT ID = 6000006



My program is

#include<iostream>
#include<string>
#include<fstream>
#include<iomanip>
#include<sstream>
using namespace std;

struct NVH
{
char name[200];
int points[200];
};




int main()

{

ifstream file;
file.open("input.txt");

ifstream pch;
pch.open("input1.txt");

char input2[300],name2[300];


ofstream pchout;
pchout.open("output.txt");


struct NVH n[200];

long int i,j,k,l,m,p,a,b,c,x,y,z,r,s,d,f;
float e;
long int g,h,t;
int u=900,v=400,w=700;
char nam[300],name[300],input[300],name1[300];
string line;











file>>nam;

file>>c;
file>>nam;
file>>nam;
for(i=0;i<c;i++)
{
file>>n[i].name;
string str("$POINT ID = ");

string replace;
replace=n[i].name;
for(p=0;p<2;p++)
{
file>>n[i].points[p];
}
x=n[i].points[0];
y=n[i].points[1];

for( j=x;j<y;j++)
{
std::stringstream tc;

tc<<j;


string integer=tc.str();


string search;
search=str+integer;
while(!pch.eof())
{
getline(pch,line);
assert(search!=replace);
string::size_type pos=0;
while ((pos=line.find(search,pos))!=string::npos)
{


line.replace(pos+search.size(),search.size(),replace);

pos++;
}
pchout<<line<<endl;
}
}
}










file.close();
pch.close();
pchout.close();
return 0;

}



I am getting output.txt by running the program as

$POINT ID = 600001Shri
I went to college
$POINT ID = 600002
I don't go to college.
It is tedious program
$POINT ID = 6000003
Shridhar Ram Rahim
$POINT ID = 6000004
Very Easy Program
$POINT ID = 6000005
Life is nice
$POINT ID = 6000006




BUT I want output.txt as

$POINT ID = 600001Shri
I went to college
$POINT ID = 600002Shri
I don't go to college.
It is tedious program
$POINT ID = 6000003Shri
Shridhar Ram Rahim
$POINT ID = 6000004Proactive
Very Easy Program
$POINT ID = 6000005Proactive
Life is nice
$POINT ID = 6000006Proactive



Please help me as I almost done the correct program but I think Only problem as you stated I could not repeat the loop in file.


Thank you in advance

[somshridhar]

Dear Sir,

Can anyone check my problem

inpt.txt is a user defined names and range of numbers which the user can change as per his requirement. The input1.txt is a file which contains $POINT ID = 600001 and so on. But it does not contain names behind it as $POINT ID = 600001shri.

So I tried to take user defined input from inpt.txt , using it in input1.txt and taking this changes in output.txt...

I am almost done this with my program for $POINT ID = 600001Shri but I COULD NOT REPEAT IT FOR THE REST OF input1.txt. Simply I think I could not repeat it for other points.(Looping Problem).

I thought I can create the file with cout<<search and I am getting correct output as
$POINT ID = 600001Shri
$POINT ID = 600002Shri
$POINT ID = 600003Shri
$POINT ID = 600004Proactive
$POINT ID = 600005Proactive
$POINT ID = 600006Proactive

But when I am trying to use it in File Management section by find and replace things I think It is not repeating loop for other points 6000002, 6000003 and so on.

So there is problem with file management section.
I used pch.clear() and pch.(0,ios::beg) so that I think the pointer will automatically reset to initial position of input1.txt but I am not getting any change in output.

Please check my program .

Thank you in advance.