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Problem with logical operator

closed account (2E0XoG1T)
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void ne(){
	cout << "bla bla";
	cin >> b1;
	cin >> b2;
	if(b1 ! b2){ 
		cout << "bla bla";
	}
	else {
		cout << "bla bla";
	}
}


Why wont this part of code ever compile?

1>------ Build started: Project: Program 13, Configuration: Debug Win32 ------
1>Compiling...
1>cpp.cpp
1>c:\documents and settings\drago\desktop\c++ programi\program 13\program 13\cpp.cpp(32) : error C2143: syntax error : missing ')' before '!'
1>c:\documents and settings\drago\desktop\c++ programi\program 13\program 13\cpp.cpp(32) : error C2059: syntax error : ')'
1>c:\documents and settings\drago\desktop\c++ programi\program 13\program 13\cpp.cpp(32) : error C2146: syntax error : missing ';' before identifier 'cout'
1>c:\documents and settings\drago\desktop\c++ programi\program 13\program 13\cpp.cpp(32) : warning C4552: '!' : operator has no effect; expected operator with side-effect
1>c:\documents and settings\drago\desktop\c++ programi\program 13\program 13\cpp.cpp(33) : error C2181: illegal else without matching if
1>Build log was saved at "file://c:\Documents and Settings\Drago\Desktop\C++ Programi\Program 13\Program 13\Debug\BuildLog.htm"
1>Program 13 - 4 error(s), 1 warning(s)
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========
closed account (1vRz3TCk)
!= (not equal) may be what you are looking for.

if(b1 != b2)
Last edited on
closed account (2E0XoG1T)
I think i said logical operator, not relational operator...
Last edited on
closed account (2E0XoG1T)
If it helps, this is whole thing:
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/*
Ovaj program demonstrira logiku
*/

#include <iostream>
#include <string>
using namespace std;

bool b1,b2;
string izbor;

void i(){
	cout << "I: ";
	cin >> b1;
	cin >> b2;
	if(b1&&b2) cout << "rjesenje je: tocno!\n";
	else cout << "rjesenje je: netocno!\n";
}

void ili(){
	cout << "Iskljucna disjunkcija: ";
	cin >> b1;
	cin >> b2;
	if(b1||b2) cout << "rjesenje je: tocno!\n";
	else cout << "rjesenje je: netocno!\n";
}

void ne(){
	cout << "Ukljucna Disjunkcija: ";
	cin >> b1;
	cin >> b2;
	if(b1 ! b2) cout << "rjesenje je: tocno!\n";
	else cout << "rjesenje je: netocno!\n";
}

void upute(){
	cout << "Ovaj program radi kao tablica za istinitosno vrednovanje slozenih izkaza.\n";
	cout << "Trenutno program podrzava \"i\", iskljucnu disjunkciju i ukljucnu disjunkciju.\n";
	cout << "Za \"i\" upisi \"i\", za iskljucnu disjunkciju \"ili\", a za ukljucnu disjunkciju \"ne\"\n";
	cout << "Nakon sto izaberes jednu od opcija upisi 0 za netocno i 1 za tocno\n";
	cout << "Za izlaz iz programa upisi \"exit\"";
}

int main(){
opet:
	cin >> izbor;
	if(izbor=="i") i();
	else if(izbor=="ili") ili();
	//else if(izbor=="ne") ne();
	else if(izbor=="upute") upute();
	else if(izbor=="izlaz") goto kraj;
	else {
		cout << "Nevaljan izbor, ako neznas kako koristiti program upisi \"upute\"\n";
		goto opet;
	}
	goto opet;
kraj:
	return 0;
}
closed account (1vRz3TCk)
I think i said logical operator, not relational operator...

Yes, you did say logical but your code suggested something else maybe if you say what you want to do...
Last edited on
closed account (2E0XoG1T)
Sorry.
I wanted the program to act like "truth table" (in logics).
Last edited on
closed account (1vRz3TCk)
try: if ( (b1 || b2) && !(b1 && b2) )
closed account (2E0XoG1T)
Resolved. Thanks.
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