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cout << armor []?

Wirsbo (2)
Hey. How would my code be if:
I want all my "armor" variables to be in an own cout, like that if a new "armor" variable is created it will be printed? 

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int armor [];
int main ()
    {
    cout << armor [] (?) << endl;
    }


Tell me if you dont understand :)
m4ster r0shi (2201)
I think I understand, but I'm not sure.

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#include <iostream>

class Armor
{
public:

    Armor() { std::cout << "new armor created!" << std::endl; }
};

int main()
{
    Armor my_armor;
    Armor more_armor;
    Armor yet_more_armor;
}
 
new armor created!
new armor created!
new armor created!

If you have trouble explaining what you want, just
write what you want the code and output to look like.
Wirsbo (2)
Hm, I mean like:

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#include <iostream>
using namespace std;

int armor [] = { 1, 2, 4, 8 };
int main;
{
    cout << "Armor:" << armor [] << endl;
}


so that all armor chars will be printed on a new line. I dont wanna repeat the "cout" line because its supposed to show the other armors if they are created.

Armor: 1
Armor: 2
Armor: 4
Armor: 8
Last edited on
m4ster r0shi (2201)
Ok, then. What you need is a for loop -> http://cplusplus.com/doc/tutorial/control/#for
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