controlling input

[spypro]

how to i limit the input to 1-9 only and when i enter a-z or A-Z it will prevent the programming from converting the input?

#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#define TIME 500
int main()
{
    int x=0,dec,rem,quo,dec1,msb=8,remArray[20];
    do
    {
     printf("\n\n\tPlease enter decimal value (1 - 999999): ");
     scanf("%d",&dec);
      if(dec>999999||dec<0)
      {
         printf("\tPlease enter value between 1 - 999999.");
         _sleep(TIME);
      }
      else if(dec<1000000||dec>-1)
      {
          for(x=0;x<msb;x++)
          {
             quo=dec/16;
             rem=dec%16;
             printf("\t16 ) %d  \t- %d\n",dec,rem);
             dec=quo;
             printf("\t   --------\n");_sleep(TIME);
          }
      }
    }while(dec>999999||dec<0)；
}

[spypro]

bump

[hamsterman]

If input fails, scanf will return EOF. You should look in a reference for things like this. When that happens, you'll probably need to clear the input stream. I'm not well familiar with c libraries, so I can only suggest while( getchar() != '\n' );.

By the way, the condition on line 17 is wrong. There is no number which wouldn't satisfy it. There is no need for a condition there at all. "else" makes sure that no number in the wrong range gets to that point.

[spypro]

i have to do a message that do "printf("\tPlease enter value between 1 - 999999.");" whenever either 'a' to 'z' or 'A' to 'Z' is input, then repeat to ask for input again...

[hamsterman]

If input fails, scanf will return EOF

When an integer is expected and a letter is written, it's a failure. Is there something you don't understand in my post?