counting characters

[Zaddock]

Input can be "a39*^$ghdG#(@"
What is the easiest way to code a program that counts letters, numbers, and other characters seperatly. Then have and output of
number of letters =
number of numbers =
number of other characters =

[mezosoft]

hi, i'm mo3taz,egypt
i've coded this program but it counts the number of characters
you can change the sellection statements to make it count the number of numbers
this is the code

#include <iostream.h>
# include <conio.h>
char previousCH, ch ,nextchar ;
int nonAlphabet  = 0 , //characters like ',' '.' ' ' ''' ......
    wordnum      = 0 , // number of words
    statenum     = 0 , // number of statements (a statement ends with (.))
    longword     = 0 , // the long word is more than 10 characters
    alphabet     = 0 , // alphabetical characters
    longtemp     = 0 , // used to count long words
    spacenum     = 0 ;  // number of spaces
/* function checks for next alphabetic characters */
bool charcheck (char c)
{
 if ((c >='a' && c <= 'z') || ((c >= 'A') && (c < 'Z')))
 return 1;
 else
 return 0;
}
//...............................

int main()
{
cout << "please enter a text paragraph ended with '$' character:\n\n";
while(nextchar != '$' )      // "$" is the end of file or input
{
 nextchar = cin.peek();
 if (nextchar == '\n')        // ignore or eat new line character
 cin.ignore(1,'\n');
 previousCH = ch;             // this character will be previous one the next loop
 cin.get(ch);
 if (charcheck(ch))
 {
   alphabet++;
   longtemp++;
   if (longtemp == 10)         // count long words
   {
    longtemp = 0;
    longword++;
   }
 }
 else
 {
  nonAlphabet++;
  //.... don't count a word if you found a space unless it was preceeded or followed with characters
  if ((ch== ',') || (ch == '.') || (ch == ' ' && (charcheck(cin.peek())) && (charcheck(previousCH))))
  {
   wordnum++;
   longtemp = 0;
   if (ch == ' ') spacenum++;
  }
  if (ch == '.')
  statenum++;
 }
}
nonAlphabet--;  // ignore '$' character
wordnum++;

 cout << "the data of this text document is:\n";
 cout << "______________________________________________________________\n";
 cout << "\nthe number of alphabetic characters is   \t:" << alphabet << endl;
 cout << "\nthe number of nonalphabetic characters  \n"
      <<"with spaces is  ..........................\t:" << nonAlphabet << endl;
 cout <<"\nwithout spaces  ..........................\t:" << (nonAlphabet - spacenum) << endl;
 cout << "\nthe number of words is ..................\t:" << wordnum  << endl;
 cout << "\nthe number of statements is .............\t:" << statenum << endl;
 cout << "\nthe number of long words is .............\t:" << longword<< endl;
getch();
}

example input:
word word word,word,word word, word. word word
word word,word,word.word$

hint: the end of text is $
itdoesn't matter to add spaces or not with "," - "." - "$"

you are welcome