Cannot figure out how to do a word count

[iNeedHelp]

Hello,

Here's the details:

User inputs sentence
Program checks sentence for 3 magic words ("chicken", "egg", "rooster")
Program keeps count of every magic word found and displays results

Here's my code:

#include<iostream>
#include<string>
using namespace std;

const string chicken( "chicken" );
const string egg( "egg" );
const string rooster( "rooster" );
const string quit( "FINISHED" );

int main () 
{

	string inputSentence;
	int w1Found, w2Found, w3Found;

	cout << "Type a sentence" << endl;
	cin >> inputSentence;

	do {

		if ( inputSentence == chicken )
		{

			w1Found++;
			

		} else if ( inputSentence == egg )
		{

			w2Found++;

		} else if ( inputSentence == rooster )
		{

			w3Found++;

		}

		cin >> inputSentence;

	} while ( inputSentence != quit );

	cout << "\"" << chicken << "\" strings found: " << word1found << endl;
	cout << "\"" << egg << "\" strings found: " << word2found << endl;
	cout << "\"" << rooster << "\" strings found: " << word3found << endl;

}

Problem with this code is that it requires EVERY sentence typed to end with "FINISHED" for it to work and know when to stop counting. I need to figure out a better way. Like:

hello blah blah chicken chicken blah egg

"chicken" found: 2
"egg" found: 1
"rooster" found: 0

But now I have to do hello blah blah chicken chicken blah egg FINISHED for it to work

[eker676]

I think your going to have to have some kind of escape sequence like FINISHED. Just make a a semi-colon or something that is only one keystroke.

[iNeedHelp]

Basically it should begin the word count as soon as the enter key is pressed, which it doesn't do if you dont include a FINISHED at the end. And it should stop at the last word (all without including any extra libraries).

So this is what happens now..

--> hello bye whats up chicken egg egg FINISHED

(1 chicken found, 2 egg, 0 rooster)

--> hello bye FINISHED

(0 everything)

--> FINISHED

(0 everything)

--> okay read this
--> comon read it and do the word count already
--> omg what the chicken is going on
--> still not reading
--> okay let me type in FINISHED

(1 chicken found)

[Zaita]

Use a map<string, int>. It's the simplest way to do a word-count.

[Duthomhas]

Sentences are normally terminated by a full stop (.), an exclamation point (!), or a question mark (?), and they may or may not be bracketed with parentheses () or square-brackets [].

Why not just check to see if the last, non-bracket character is one of the sentence terminators? If it is, then you know to stop reading.


A couple of other comments. I don't know if your professor has asked you to do this or not, but things like

  #define one 1
  const string rooster = "rooster";

etc. are quantifiably, er, stupid --though you will find such spread around a lot of code. If you are checking for a rooster, check for the rooster directly, instead of using some "constant" that someone may have changed on recompilation.
else if (inputWord == "rooster")

The other comment is about how you check the input word. What if the user inputs:

I wish I were a rooster, but I am not.

or

Roosters make for happy hens.

(sorry :-P)
In both cases, the simple == operator will fail to identify them. You need to
1 Normalize them (convert the input to upper- or lower-case), and
2 Search for them using one of the string::find() functions.

Hope this helps.