parse an int?

[mrmts]

Im fairly new to C and C++, having been learning for four months now.

I'm curious to know if I can parse an int to check for a non-digit character entered. I know I could use a string of char's and use !isdigit() for each char, but I just want to know if there is a similar way for int's?

here are the important parts:

#include <cstdlib>
#include <iostream>
#include <cctype>

typedef struct
{
    char name[20],email[50],phone[7];
    long id;
    
}students;

/*function protos*/   
void edit(students *vals);

int main(int argc, char *argv[])
{
  students stu[40];

  /*pointer to first array of struct*/
  students *sptr = stu;

  edit(sptr); //pass ptr to function
} 

void edit(students *vals)
{   
    int record=0;

while(1)
    {
        cout << "\n\t\t" << "Enter the student id [numbers only]:\t";
        cin  >> vals[record].id;
        
        if(vals[record].id  ) /* what to put here? */
            continue;
        else
            break;
    }
}

[helios]

"Parsing an int" has no meaning. An int is information that is already understandable by a computer (as opposed to, say, "1024").
After the cin, you already have an integral value in vals[record].id. There's no processing to be done.

[mrmts]

what if a char is entered.. program would crash b/c it is expecting an int?

[helios]

Have you ever tried it? 'Cause I have, and that's not what happens.

#include <iostream>

int main(){
	int a;
	std::cin >>a;
	std::cout <<a<<std::endl;
	return 0;
}