'A' || 'a' problem.

[HeatMan]

How we can check if a variable (example "choice") is 'A' or 'a', but without using ||?

[firedraco]

If its a char, just use tolower() or toupper().

[HeatMan]

Uhm... How? Can you give an example, please?

[firedraco]

//assuming 'a' is a char
if(toupper(a) == 'A')
//or
if(tolower(a) == 'a')

[jsmith]

I gotta hear why you don't want to use ||.

So would this suffice:

if( !( a != 'a' && a != 'A' ) ) { }

:)

[HeatMan]

Thanks both! (Sorry for not saying that earlier...)