How to fill x[i] from array[8][8]?

[Zemtriz]

#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    srand (time(NULL));
    
    int pole[8][8] = {0};
    pole[1][2] = 1;
    pole[2][2] = 1;
    pole[3][2] = 1;
    pole[4][2] = 1;
    pole[4][3] = 1;
    pole[4][4] = 1;
    pole[3][4] = 1;
    pole[5][4] = 1;
    pole[4][5] = 1;
    pole[6][4] = 1;
	for (int nRow=0; nRow < 8; nRow++)
    {
        for (int nCol = 0; nCol < 8; nCol++)
        cout << pole[nRow][nCol] << " ";
        cout << endl;
    }

    double activation = 0;
    for (int i=0; i<64; i++)
    {
        double x[i],w[i];
        activation += x[i] * w[i];
    }
    
    system("PAUSE");
    return EXIT_SUCCESS;
}

I want to fill x[i] with numbers from my array. Like x[10] will be assigned with number 1. Thanks.

[Zemtriz]

Got it. But can it be written like this?

#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    srand (time(NULL));
    
    int pole[8][8] = {0};
    pole[1][2] = 1;
    pole[2][2] = 1;
    pole[3][2] = 1;
    pole[4][2] = 1;
    pole[4][3] = 1;
    pole[4][4] = 1;
    pole[3][4] = 1;
    pole[5][4] = 1;
    pole[4][5] = 1;
    pole[6][4] = 1;
	for (int nRow=0; nRow < 8; nRow++)
    {
        for (int nCol = 0; nCol < 8; nCol++)
        cout << pole[nRow][nCol] << " ";
        cout << endl;
    }

    double activation = 0;
    for (int i=0; i<64; i++)
    {
        double x[i],w[i];
        for (int nRow=0; nRow < 8; nRow++)
        {
            for (int nCol = 0; nCol < 8; nCol++)
            x[i] = pole[nRow][nCol];
        }
        activation += x[i] * w[i];
    }
    
    system("PAUSE");
    return EXIT_SUCCESS;
}

Or is there any better way? °¸°

[webJose]

It seems that you are programming a neural network? Looks strange though.

Anyway, check out the STL algorithms for_each() and generate(). See http://www.cplusplus.com/reference/algorithm/. I would use generate() to initialize the pole matrix, and then I would use for_each() to calculate x[] and activation.

[Zemtriz]

Thanks for reply. But I do not understand how to write it to generate 8×8 cells. And you're right. It will be a simple neural network, which will recognize number 4 from that. If it'll be 4, then it will return 1. If not = 0. Every cell represent one input.

00000000
00100000
00100000
00101000
00111100
00001000
00001000
00000000

[moorecm]

Are you just trying to use for loops to convert between 1D and 2D arrays?

You can calculate the indicies with something like this:

// let C represent the row-size of the 2D array
for( int y = 0; y < v2d.size(); ++y ) {
    for( int x = 0; x < C; ++x ) {
        v1d[y * C + x] = v2d[y][x];
    }
}

Or (going the other way):

for( int i = 0; i < v1d.size(); ++i ) {
    v2d[i / C][i % C] = v1d[i];
}