For-loops

[pastamaker]

How could I get a program to generate something like this? It displays 1 and 2 the same increasing amount of times until it gets to six.

121122111222111122221111122222111111222222

I feel like this should be really easy but I can't quite place what I need to do. I would think a for-loop would work here but I might be wrong.
Thanks!

[Intrexa]

You need to use a nested for loop, the end result would look like this:

for(int i = 0; i < 6; i++)
{
   for(int j = 0; j < i +1; i++)
   {
       //output
   }
}

[Shinra Tensei]

An alternative, yet quite likely worse solution is:

   int i = 1;
   int j = 2;

   int k = 1;
   while (k < 6) {
        for (int l = 1; l < k + 1; l++)
            cout << i;
        for (int m = 1; m < k + 1; m++)
            cout << j;
        k++;
   }

[firedraco]

@Above Posters: Don't just post code, it generally helps more if you just try to give tips so that the OP can discover it on their own.

[D80DSL3A]

How about this silly method? It needs just one for loop!
@pastamaker: This is probably NOT how you are supposed to do it (for your assignment).
@firedraco: Sorry, but it looks like the cat's out of the bag already, plus it's a goofy method.

char ones[7], twos[7];
for(int k=1; k<=6; ++k)
{
	ones[k-1] = '1';// write another '1' to the array
	ones[k] = '\0';// move the string end forward
	twos[k-1] = '2';// likewise
	twos[k] = '\0';
	cout << ones << twos;
}