how to alloc this

[codder]

Hi all,

void myfunc(type **t)
{
// i want to alloc it
}

int main()
{
type *a = NULL;
myfunc(&a);
if(!a)
//error...

a->....
...
return 1;
}

i tried
t = new type*;
(*t) = new type();

but it crash...

[anonymous23323124]

What exactly are you trying to allocate? What is type? Do you want to allocate a single element, or an array. If it is the second one, how are you going to tell myfunc this?

[codder]

type is a structure like this

struct type
{
type();
~type();

void func1();
void func2();

};

[anonymous23323124]

i tried

(*t) = new type();

but it crash...

This one should work, as far as I can see. What is in the type constructor?

[edit]And, of course, Remember to free allocated memory before you quit :)

[codder]

struct type
{
type();
~type();

void *mem;
long len;
}

type::type() : mem(0), len(0)
{
}

[anonymous23323124]

Run your debugger and you should be able to discover exactly where the error is.

As a guess, do try to free mem in your destructor without checking if it's zero?