Mixed loops?!

[DGvMDjzh]

Ive been messing around with loops lately and I noticed how strangely for loops behave in a while loop.

void ForLoop1() {
  for(int i = 0; i < 100; i++) cout << "1looping" << i << endl;
}


void ForLoop2() {
  for(int i = 0; i < 100; i++) cout << "2looping" << i << endl;
}

int main() {
  while (clock() != -1) {
    ForLoop1();
    ForLoop2();
  }
  return 0;
}

The while loop completely ignores the second for loop, thus repeatedly loading the first for loop. Although this works if I convert all loops to while. This logic confuses me. I would appreciate an explanation for this weird behavior. And if possible, how to solve it with out converting all the sub loops to while.

[quirkyusername]

that's not true, you've just not initialised 'i' in your for loop so its probably entering ForLoop1() only once and checking an uninitialised variable against 100, and looping forever

EDIT - I'm surprised you dont get either a crash or some kind of run-time check error, what compiler are you using?

EDIT 2 - Interracial?

[DGvMDjzh]

And what do you mean I didn't initialize i? Doesn't int i = 0; "initialize" it?
A1: I'm using code blocks.
A2: I guess it wasn't the best choice of words :S

[coder777]

Doesn't int i = 0; "initialize" it?

It does. But line 2/7 doesn't.

A2: I guess it wasn't the best choice of words :S

You might take a deeper look at your dictionary