"expected ';' before string constant error"

[jacobsaunders93]

Hi

I'm building a fraction calculator in C++ & I've ran into the error: "expected ';' before string constant" & I can't figure out whats wrong with it. Here is my code:
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int FracPer () {
cout << "You have entered reading fractions & their percentage!" << endl;
cout << "Please enter the numerator: " << endl;
cin >> numer1;
cout << "Please enter the denominator you want to place under " << numer1 << ": ";
cin >> denom1;
frac1 = numer1 "/" denom1;
percent = (numer1 / denom1) * 100;
cout << "The whole fraction you have entered is " << frac1 << " & its percentage is " << percent << ".";
cout << endl << endl;
}
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The error is in the line frac1 = numer1 "/" denom1;. Please help me if you can!

Thanks
Jacob Saunders

[Moschops]

frac1 = numer1 "/" denom1;

What is that meant for? It's causing the error.

If you're trying to concatenate strings, the syntax to do so with std::string type is "+", as in

frac1 = numer1 + "/" + denom1;

[Zhuge]

Considering what the OP is doing on the next line, it seems like numer1 and denom1 are numerical values...? So if that's right, just remove the quotes around the / and possibly make sure you doing floating point division if that's what you want.

[Albatross]

Ah, if only C++ was PERL. ;)

For this to work, you will need to make a cast from a string type (like std::string) to an integral type, or vice-versa. C++ won't implicitly convert between them.

Here's a way to convert from an int into a string (I'm assuming numer1 and denom1 are numeric).
http://notfaq.wordpress.com/2006/08/30/c-convert-int-to-string/

Good luck!

-Albatross

P.S: Are numer1 and denom1 ints? If they are, you might have some problems with the division.

[Computergeek01]

Here's another way to convert an int into a string: http://www.cplusplus.com/reference/iostream/stringstream/

EDIT: Did anyone else notice that none of these variables seem to be declared in this function? Or am I just missing it?