Char arrays

[fulmermike]

Assignment is to loop through two data files and compare the answers to find the number of correct answers.Then produce a report that shows what responses were given to the 20 questions.This second part includes a 2-D array of counters.What I have that works for the first section is as follows:
#include<fstream>
#include<iostream>
#include<iomanip>
using namespace std;
void main()
{
ifstream finans,fintests;
char key[21],idno[23],responses[21];
int i=0,j=0,count=0, numcorrect=0,counter[21][6]={0};

finans.open("answers.dat");
fintests.open("tests.dat");
finans>>key;
fintests>>idno>>responses;
cout<<setw(20)<<"student id"<<setw(40)<<"number correct"<<endl;
cout<<endl;
while(!fintests.eof())
{
count++;
for(i=0;i<20;i++)
{
if (responses[i]==key[i]&&responses!="")
numcorrect++;
counter[i][j]++;



}
cout<<setw(20)<<idno<<setw(40)<<numcorrect<<endl;
cout<<""<<endl;

numcorrect=0;
fintests>>idno>>responses;

}
cout<<"number of students taking exam="<<count<<endl;
for(i=0;i<20;i++)
for(j=0;j<5;j++)
counter[i][j]++;
cout<<counter[i][j]<<"";

cout<<" "<<endl;
//fintests>>idno>>responses;

}


This produces the following output:

student id number correct

430-52-6192 13

112-81-5225 19

120-49-5322 12

456-65-3211 2

990-45-0978 4

324-98-5445 6

112-34-3443 12

435-56-8790 18

452-23-5675 6

776-45-5454 7

567-71-9909 6

345-54-7834 9

555-12-2341 18

568-09-0096 20

664-61-0987 10

612-45-7687 5

567-23-1125 3

561-43-6781 6

498-12-4321 3

479-01-4867 4

489-90-0999 17

456-09-1111 19

561-66-6657 3

number of students taking exam=23
0
Press any key to continue . . .

The second part should look like this:

Question A B C D E

1 5 1 13 3 1
2 4 7 1 7 4
3 etc..........

I am not making any headway on the second part.Would be happy to post my numerous attempts if anyone is interested.Any help is appreciated

[methodos]

You could try first casting the characters as int's and then add one to the counter set per question i and per responses[i]:

for(i=0;i<20;i++)
{ 
	if (responses[i]==key[i]&&responses!="")
	{
		numcorrect++;
	}
	//cast as int
int respons[21];
	respons[i]=(int)responses[i]-'A';
	//counter gets larger for every respons[i] to question i
		counter[i][respons[i]]++;
}

then to output do something like :

cout << setw(3) << i+1 <<  " ";
	for(j=0;j<5;j++)
	{
		
		cout<< setw(3) << counter[i][j] <<" ";
	}