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switch (default)

bluesky44 (2)
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#include <stdio.h>
#include <conio.h>
int main()
{
    int a,b;
    int c;
    printf(" ilk sayıyı giriniz ; \n ");
    scanf("%d",&a);
    printf(" ikinci sayiyi giriniz ; \n ");
    scanf("%d",&b);
    printf(" Bir işlemci giriniz ( 1 2 3 4 ) ; \n ");
    scanf("%d",&c);
    switch(c)
    {
    case'1':
    printf(" %d ",(a+b));
    break;
    case '2':
    printf(" %d ",(a-b));
    break;
    case '3':
    printf(" %d ",(a*b));
    break;
    case '4':
    printf(" %d ",(a/b));
    break;
    default:
    printf("bilinmeyen işlemci sectiniz");
}
getch ();         
return 0;
}



hi. :) I am a C user. i get 'bilinmeyen işlemci sectiniz' message when i enterred ' 1 '. why don't i see case (1) in screen? Can you help me? I am sorry for my English ;)
thank you. :)
coder777 (8444)
Because '1' != (int) 1. '1' -> is ASCII value 48

So omit the ''
bluesky44 (2)

coder777
Ah, okay. thank you. ;)
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