Help with for loop

[eze123]

I'm making a code that will recieve the dimensions for four rooms and then add them together and give me variable totalSqFeet. I have to use a for loop to achive this and idk how to take the separate values from each room. It's hard to explain here is the coding i have so far any help?


// Ethan Hernandez COSC-1436-2001
#include <iostream>
#include <string>
using namespace std ;
int main ( )
{
double width ;
double length ;
double room ;
double totalSqFeet ;
const double carpetWidth = 15 ;
const double sqFeetPerYard = 9 ;
double squareYards ;
double linearFeet ;
int counter ;

cout << " \t Ethan Hernandez Assignment L \n Ethan's Carpet Store " ;

for ( counter = 0 ; counter < 4 ; counter ++ )
{
cout << " \n \n What is the width in feet? " << counter + 1 << " \t " ;
cin >> width ;
cout << " What is the length ? " << counter + 1 << " \t " ;
cin >> length ;
if ( width < 10 || width > 50 )
{
cout << " \n Width is not between 10 and 50 " ;
width = 0 ;
}
if ( length < 10 || length > 50 )
{
cout << " \n Length is not between 10 and 50 " ;
length = 0 ;
}

room = width * length ;

cout << " Area of room is " << room ;

}

system("Pause") ;
return 0 ;
}


P.S. there is more to this program that is why their is more variables but i just need help on this section.

[sasanet]

use code tag next time.
ok now let's look at this...

#include <iostream>
#include <string>
using namespace std ;
int main ( )
{
double width ;
double length ;
double room ;
double totalSqFeet ;
const double carpetWidth = 15 ;
const double sqFeetPerYard = 9 ;
double squareYards ;
double linearFeet ;
int counter ;

cout << " \t Ethan Hernandez Assignment L \n Ethan's Carpet Store " ;

for ( counter = 0 ; counter < 4 ; counter ++ )
{
cout << " \n \n What is the width in feet? " << counter + 1 << " \t " ;
cin >> width ;
cout << " What is the length ? " << counter + 1 << " \t " ;
cin >> length ;
if ( width < 10 || width > 50 )
{
cout << " \n Width is not between 10 and 50 " ;
width = 0 ;
}
if ( length < 10 || length > 50 )
{
cout << " \n Length is not between 10 and 50 " ;
length = 0 ;
}

room = width * length ;

cout << " Area of room is " << room ;

}

system("Pause") ;
return 0 ;
}

if u need total square of 4 rooms then u should create array of 4 fooms
so: double room [4];

then if user's input is not correct you should add goto statement to repeat asked until answer is corrct ( or better is to use while than goto)

once u putt all squares into room array make sum of that array.

[eze123]

oh i'm sorry about that...

[Codefreak101]

1. Don't be sorry about making mistakes, that's why the forums was created.

2.NEVER USE A GOTO. If you need to know why, google Goto Statement Dangerous.

3.Why is the carpet width a const if the area of the rooms changes? Is the width of the rooms combined maxed at 15, or is it for each room?

[TrevorD]

if ( width < 10 || width > 50 )
{
cout << " \n Width is not between 10 and 50 " ;
width = 0 ;
}
if ( length < 10 || length > 50 )
{
cout << " \n Length is not between 10 and 50 " ;
length = 0 ;
}

Firstly, your input validation for the length and width just poses the question whether they are within the constraints, what you should do is use a while loop.. Like this

While ( length < 10 || length > 50 )
{
  cout << "Length is not ... blah blah";
  cin >> length;
}

You we're on the right track, but you want to make sure that you still get the Input from them despite that they entered a wrong number.