How would I write a definition of the function?

[KentuckyNative]

This is what I have so far.

//-----------------------------------------------------------------------------------------
//
//  Function: tempAvg ()
//
//	Parameters:	
//    input tempArray: double; array of temperatures
//    input days: integer; number of days for that month
//    input times: integer; number of times temperature is measured each day 
//                    for that month
//    
//	Pre-condition: input array must be populated with valid temperatures;
//                 input number of days must be between 28 and MaxDays (inclusive)
//                 input number of times must be at least one less than MaxTimes
//  Post-condition: The average temperature for each day is calculated and 
//                  stored in the last column of the array 
//-----------------------------------------------------------------------------------------

void tempAvg (double [][MaxTimes], int, int);

And I need to Write the complete definition of the function tempAvg () making sure the post condition is met.

This is what I have so far.

void tempAvg (double tempArray[][MaxTimes], const int days, const int times)
{
    for(int i = 0; i < days; i++)
    {
        for(int j = 0; j < times; j++)
}

[sasanet]

hello!
here is the function definition:

void tempAvg (double tempArray [maxDays] [maxTimes], int days, int times) {
	if (days > maxDays || days < 28 || times >= maxTimes) exit (1);
	double sum = 0; 
	for (short d = 0; d < days; d++) {
		for (short t = 0; t < times; t++) {
			sum += tempArray [d] [t];
		}
		tempArray [d] [maxTimes] = sum / times; 
		sum = 0;
	}
}

and here is example and explanation:

#include <iostream>
using namespace std;

const int maxDays = 31;
const int minDays = 28;
const int maxTimes = 31;  // here is one more then allowed which is reserved for last column!!


void tempAvg (double [maxDays] [maxTimes], int, int);

int main () {
	//example:
	double test [maxDays] [maxTimes];  //regardles of how many days there relay are we must use universal arrays which are compatible with function

	short days = 3, times = 2;
	double temperature;

	for (short d = 0; d < days; d++)
		for (short t = 0; t < times; t++) {
			cout << "enter temperature for day nr. : " << d + 1 << " and time nr. : " << t + 1;
			cin >> temperature;
			test [d] [t] = temperature;  // let's initilize array with some temperatures
		}
	cout << "-----------------------------------------------";
	//lets calculate average for each day
	tempAvg (test, days, times); //and here we will specife real days and times...user is responsible to enter correct days and times

	// now let's display average for each day:
	for (short d = 0; d < days; d++)
		for (short t = 0; t < times; t++)
			cout << "avgTemp day: " << d + 1 << " is: " << test [d] [maxTimes] << endl;

	system ("pause");
	return 0;
}
void tempAvg (double tempArray [maxDays] [maxTimes], int days, int times) { /*maxDays + 1 is the last column reserved for average temperature
array second dim. must be maxDays + 1 regardles of real days but argument days will tell us how wide array is (until where members are active values ---other are inactive so skiped in inside for!!!*/
	if (days > maxDays || days < 28 || times >= maxTimes) exit (1); //check if rules are broken
	double sum = 0; //hold sum of temperature here for each day then reset
	for (short d = 0; d < days; d++) {
		for (short t = 0; t < times; t++) {
			sum += tempArray [d] [t]; //add to the sum for each measure in this day  ---> note d are days and t is times
		}
		tempArray [d] [maxTimes] = sum / times; // exiting inside for so last column for this day hold average for day of outside for (sum / times)
		sum = 0; //reset sum for this day! --> day D :)
	}
}

it would be much beter to do this with pointers and dynamic memory but that was not the question :)

[KentuckyNative]

Thanks alot.

You explained it to me perfectly.

Once again thanks. I now understand it.

[firedraco]

@sasanet: Don't just give complete solutions, try to give hints instead. You learn more if you solve for the solution yourself than if you read something someone else gave you.

[Zhuge]

@sasanet: Avoid giving out complete solutions in the future. There are many who will simply take your code and turn it in as their own, learning nothing.

[KentuckyNative]

Yeah but this was very informative. I turned this code into my own.

[chrisname]

You might have learned more if you had been told how to do it rather than given it. In this instance, I think sasanet explained it well, though. Some people, though, are just lazy and ask for complete solutions, copy them, and then don't understand what the code actually does.