Delay after cout

[adrianooo231]

Hi

I want to make a (fake) loading screen before my program i would like it to look like

L(1sec delay)o(1 sec delay) a (1sec delay) and so on here is my code

cout << "L" << endl;
cout << "o" << endl;
cout << "a" << endl;
cout << "d" << endl;
cout << "i" << endl;
cout << "n" << endl;
cout << "g" << endl;
cout << "." << endl;
cout << "." << endl;
cout << "." << endl;

[PanGalactic]

On Unix/Linux, you have various sleep() functions. I believe Windows provides something similar with Sleep().

[Codefreak101]

Anyone know how to use that on windows that could explain it I'm kind of intrigued I've always wondered about actually using time.

[king214]

To try and make it more portable you could use #include <ctime> to make a timing function, but I would definately be easier just to what PanGalactic said(I think...).

[Stupebrett]

You could do it this way, as PanGalactic said:

#include <iostream>
#include <Windows.h> //you need this header to use Sleep()

using namespace std;

int main()
{
	cout << "L" << endl;
	Sleep(1000); //this pauses the program for 1000 milliseconds (1 second)
	cout << "o" << endl;
	Sleep(1000);
	cout << "a" << endl;
	Sleep(1000);
	cout << "d" << endl;
	Sleep(1000);
	cout << "i" << endl;
	Sleep(1000);
	cout << "n" << endl;
	Sleep(1000);
	cout << "g" << endl;
	Sleep(1000);
	cout << "." << endl;
	Sleep(1000);
	cout << "." << endl;
	Sleep(1000);
	cout << "." << endl;
	Sleep(1000);
	return 0;
}

[Codefreak101]

Oh that's awesome I thought there would be something like that I just never found it.