passing by reference const

[Blessman11]

how do you pass by reference without altering its contents. So far I realized that putting const can alter its values but not the reference

[Blessman11]

Is it possible at all to pass by reference and not change its value.

[oldnewbie]

func(const int& myint) ?

[D80DSL3A]

Yes. If a function f() takes a value x this way:
f( const int& x )// using type int for example but this applies to any type
Then any code within f() that would change the value of x will cause an error.
Here x is passed by reference but its value cannot be changed.