Cin state ignore white spaces

[o10S216C]

    88        cout << "nAccount #: " << i + 1 << endl;
    89        cout << "Enter First Name: ";
    90        cin.ignore();
    91        cin >> account[i].firstName, SIZE;
    92        cout << "Enter Last Name: ";
    93        cin.ignore();
    94        cin >> account[i].lastName, SIZE;
    95        cout << "Enter Address: ";
    96        cin.ignore();
    97        cin >> account[i].address;
    98        cout << "Enter City: ";
    99        cin.ignore();
   100        cin >> account[i].city;
   101        cout << "Enter State: ";
   102        cin.ignore();
   103        cin >> account[i].state;
   104        cout << "Enter Phone Number: ";
   105        cin.ignore();
   106        cin >> account[i].phoneNum;
   107        cout << "Enter Account Balance: ";
   108        cin.ignore();
   109        cin >> account[i].acctBal;
   110        cout << "When is the Last Payment Due? ";
   111        cin.ignore();
   112        cin >> account[i].lastPay;

[hanst99]

And now? How should anyone guess what you are trying to ask from this? btw:

cin >> account[i].lastName, SIZE;

This doesn't make any sense. I don't know what you think it does, but I can guarantee you it doesn't.

[o10S216C]

Let the user enter data including white spaces with a cin.ignore() statement but, the way i have it doesnt work.

Enter Address: 1234 Houston
Enter City: Enter State: 

thats what it spits out when i use white space in the cin statement before it.
its suppose to look like this

Enter Address: 1234 Houston
Enter City: Houston
Enter State: TX

[oldnewbie]

As I know cin stops reading when it sees a white space.
cin.get() reads also whitespaces.