Swapping pointers or Swapping Addresses?

[ToniAz]

Hello Everyone!

I'm a bit lost, what's the difference between this sample I've just came across

int a = 10;
int b = 99;
int * pa = &a;
int * pb; 
pb = &b;
int t = *pa;
cout << "t = " << t << endl;
*pa = *pb;
*pb = t;

and this sample (what I usually do):

int *pt = pa;
pa = pb;
pb = pt;

Thanks!

[hanst99]

Well, one has 9 lines of code, and yours has 3.

Also, this

int *pt = pa;
pa = pb;
pb = pt;

Will swap the addresses pa and pb point to respectively, and this:

int t = *pa;
*pa = *pb;
*pb = t;

Swaps the values of the memory regions pointed to by the pointers.