Problem with palindrome

[soysause]

Hey guys, i'm having problems with my palindrome function. Sometimes when it is a palindrome with a space it declares that it isnt a palindrome and if there's a punctuation in the end, it declares it isnt a palindrome. Any suggestions?

void palindrome () 
{
	char word[256];	//how to ignore other data type
	int length, i, j;

	cout << "Enter a word, phrase or sentence: ";
	cin >> word;
	length = strlen(word);
		for(int i=0; i < length-1; i++)
		{
			if(ispunct(word[i]||isspace(word[i])))
				word[i]= 'b';
		}
		for (i=0, j=length-1; j>i; j--, i++)
		{

			if((word[i]) != (word[j]))
			{
				cout <<"No it is not a palindromen" << endl;
			}
			else 
				cout <<"Yes, it is a palindromen"<< endl;
		break;
		}
	cout << "Press <enter> to continue.. ";
	fflush ( stdin );
	cin.get ();
}

[Browni3141]

It shouldn't even work for palindromes without punctuation. Try racecar, and I'm sure it won't work. I'm sorry to say that your logic has several major flaws.
line 11,12:

if(ispunct(word[i]||isspace(word[i])))//you're missing a parenthesis before ||
    word[i]= 'b';//why 'b'? That doesn't help anything 

Your second for loop is also not going to work. You're breaking after the first comparison every time.

I recommend setting up a loop for the input and ignoring any invalid characters.

[propohetjohn]

and what's up with the break statement? your for loop is not a for loop at all since you're breaking out of it during the first iteration no matter what