thread stopped?? ..

[yamcake01096]

ok this is my coding and im using the borland c++ compiler

edit: sori for not usin the tag codes, i still don't know whats wrong, never get a thread error before..

#include<iostream>
#include<conio.h>
#include<iomanip.h>

void getProblem();
void get2Pt();
float SlopeInteptFrom2Pt(float,float,float,float);
float display2Pt(float,float,float,float);

void getPtSlope();
float InteptFromPtSlope(float,float,float);
float displayPtSlope(float,float,float);

float displaySlopeIntept(float,float);

void main()
{
	getProblem();
	getch();
	return;
}

void getProblem()
{
	int choice;
   char conv='y' ;
   while (conv=='y'||conv=='Y')
   {
		cout<<"Select the form that you would like to convert to slope intercept form:"<<endl;
   	cout<<"1)	Two- point form ( you know two points on the line)"<<endl;
   	cout<<"2)	Point -slope form ( you know the line's  slope and one point)"<<endl;
      cout<<endl;
      cin>>choice;

      switch (choice)
      {
      	case 1:
         get2Pt();
         break;

         case 2:
         getPtSlope();
         break;

         default:
         cout<<"Error! Incorrect choice"<<endl;
      }

      cout<<"Do another conversion (Y or N)"<<endl;
      cin>>conv;
   }
}

void get2Pt()
{
	float x1, y1, x2, y2;
   cout<<"Enter the x- y coordinates of the 1st point separated by a space"<<endl;
   cin>>x1>>y1;
   cout<<"Enter the x- y coordinates of the 2nd point separated by a space"<<endl;
   cin>>x2>>y2;
   display2Pt(x1, y1, x2, y2);
   SlopeInteptFrom2Pt(x1, y1, x2, y2);
}

float display2Pt (float x1, float y1, float x2, float y2)
{
	cout<<"Two-point form"<<endl;
   cout<<"m = ";
   cout<<setiosflags(ios::fixed)<<setprecision(2)<<y2;
   if (y1<0)
   cout<<"+";
   else
   cout<<"-";
   cout<<setiosflags(ios::fixed)<<setprecision(2)<<y1<<endl;
   cout<<"_________"<<endl;
   cout<<setiosflags(ios::fixed)<<setprecision(2)<<x2;
   if (x1<0)
   cout<<"+";
   else
   cout<<"-";
   cout<<setiosflags(ios::fixed)<<setprecision(2)<<x1<<endl;
}

float SlopeInteptFrom2Pt (float x1, float y1, float x2, float y2)
{
	float slope, b;
   slope = (y2-y1)-(x2-x1);
   b = y2-(slope*x2);
   displaySlopeIntept(slope, b);
}

void getPtSlope()
{
	float x1, y1, slope;
   cout<<"Enter the slope"<<endl;
   cin>>slope;
   cout<<"Enter the x- y coordinates of the point separated by a space"<<endl;
   cin>>x1>>y1;
   displayPtSlope(x1, y1, slope);
   InteptFromPtSlope(x1, y1, slope);
}

float displayPtSlope(float x1, float y1, float slope)
{
	cout<<"Point-slope form"<<endl;
   cout<<"y";
   if (y1<0)
   cout<<"+";
   else
   cout<<"";
   cout<<setiosflags(ios::fixed)<<setprecision(2)<<y1;
   cout<<"=";
   cout<<setiosflags(ios::fixed)<<setprecision(2)<<slope;
   cout<<"(x";
   if (x1<0)
   cout<<"+";
   else
   cout<<"";
   cout<<setiosflags(ios::fixed)<<setprecision(2)<<x1;
   cout<<")"<<endl;
}

float InteptFromPtSlope (float x1, float y1, float slope)
{
	float b;
   b=y1-(slope*x1);
   displaySlopeIntept(slope, b);
}

float displaySlopeIntept(float slope, float b)
{
	cout<<"y = "<<slope<<"x ";
   if (b>=0)
   cout<<"+ ";
   else
   cout<<"";
   cout<<b<<endl;
}

and the question is

2. Table 5.6 Mathematical models of nonvertical straight lines.

|Model| |Equation| |Given|

|Two point form| | m= y2- y1/x2-x1| |(x1,y1),(x2,y2)|

|Point slope form| | y-y1 = m(x-x1)| | m,(x1,y1) |

|Slope intercept form| |y = mx + b| | m,b |

Table 5.6 summarizes three commonly used mathematical models of nonvertical straight lines.

Design and implement a program that permits the user to convert either two- point from or point -slope from into slope- intercept form. Your program should interact with the user as follows:

Select the form that you would like to convert to slope intercept form:
1) Two- point form ( you know two points on the line)
2) Point -slope form ( you know the line’s slope and one point)
= >2
Enter the slope => 4.2
Enter the x- y coordinates of the point separated by a space => 1 1

Point- slope form
y – 1.00 = 4.20 (x-1.00)

Slope- intercept form
y = 4.20x – 3.20

Do another conversion ( Y or N) => Y

Select the form that you would like to convert to slope intercept form:
1) Two -point form ( you know two points on the line)
2) Point -slope form ( you know the line’s slope and one point)
= >1
Enter the x- y coordinates of the 1st point separated by a space => 4 3
Enter the x- y coordinates of the 2nd point separated by a space => - 2 1

Two- point form
m= (1.00-3.00)
------------
(-2.00- 4.00)

Slope- intercept form
y = 0.33x + 1.66

Do another conversion ( Y or N) => N

Implement the following functions :

getProblem – Display the user menu, then inputs and returns as the function value the problem number selected.

get2Pt - Prompts the user for the x-y coordinates of both points, inputs the four coordinates, and returns them to the calling function through output parameters.

getPtSlope - Prompts the user for the slope and x-y coordinates of the point, inputs the three values, and returns them to the calling function through output parameters.

SlopeInteptFrom2Pt – takes four input parameters, the x-y coordinates of two points, and returns through output parameters the slope (m) and y-intercept (b)

InteptFromPtSlope - takes three input parameters, the x-y coordinates of one point and the slope, and returns as the function value the y-intercept

display2Pt - – takes four input parameters, the x-y coordinates of two points, and displays the two point form line equation with a heading.

displayPtSlope - takes three input parameters, the x-y coordinates of one point and the slope, and displays the point slope form line equation with a heading.

displaySlopeIntept - takes two input parameters, the slope and y- intercept, and displays the slope intercept form line equation with a heading

it executes succesfully, but after the coordinates is inputted, this error popped up

thread stopped
fault: floating point stack

... any idea how to fix this?

[mahlerfive]

Once I changed main to return int, and returned 0 at the end of it, it would compile for me. Ran it and it seemed to work fine...