Declaring int only once.

[anzki4]

Just got in to a problem; how do you declare int just once, in the beginning of a program.

Example:

int function(int a,int b)
{
   int something=10-b;
   return(something);
}

int main()
{
   int something=1; //Goal is this would be declared just one time.
   int x=function(something,2);
   cout << something; //Goal is that here it would print int returned from function.
}

[Chazzmundo]

You are setting the int you return to a variable 'x'.

Therefore to print out the returned int, change your cout so it is the following:

int function(int a,int b)
{
   int something=10-b;
   return(something);
}

int main()
{
   int something=1; //Goal is this would be declared just one time.
   int x=function(something,2);
   cout << x; //Goal is that here it would print int returned from function.
}

Your other problem is that your 'something' variable in the int main() gets passed to your function but not actually used. Therefore create a pointer within your main and pass the value by reference so that your code looks like this:

void function(int *a,int b)
{
   *a= *a-b;
}



int main()
{
   int something=1; //Goal is this would be declared just one time.
   function(&something,2);
   cout << something<<endl; //Goal is that here it would print int returned from function.

}

I think your aiming for the first code answer I gave, but the second shows how to change the something variable declared in the main without actually returning it.

[anzki4]

Thank you.