stupid question

[navderm]

Hi All,

In a base class if I have a function in protected scope, I get that in private in the derived class.

what if i want it in protected scope of the derived class too?


~Cheers!
navderm

[jsmith]

You can:

1) inherit publicly (which changes what's in the derived class' public interface) OR
2) use the "using" clause to lift in into the protected section.

Example of latter:

struct Base {
    protected:
        void foo();
};

struct Derived : protected Base {
    protected:
        using Base::foo;
};

[Bazzy]

If you have a protected member, it will still be a protected member in the derived class if you inherit publicly