Passing an array to a function:

[boredToDeath]

Hi, I've been trying for hours to find out the error in this program, it has something to do with passing the array to the function, here is the program:

#include <iostream>
using namespace std;
bool identical(int, int, int);

void main()
{
	int a[99999], b[99999], n;
	bool check;

	cout<<"Please enter the number of integers per set: ";
	cin>>n;

	cout<<"Please enter the integers of the fist set:\n";
	for (int i=0; i<n; i++)
		cin>>a[i];
	cout<<"Please enter the integers of the second set:\n";
	for (int j=0; j<n; j++)
		cin>>b[j];

	check = identical(a[], b[], n);

	if (check == true)
		cout<<"The two sets are identical";
	else
		cout<<"The two sets are identical";
}

bool identical(int a[], int b[], int n)
{
	bool end = false;
	for (int i=0; i<n; i++)
		if (a[i]!=b[i])
		{
			return false;
			end = true;
		}
	if (end == false)
		return true;
}

And the error is:
........program 3.cpp(20) : error C2059: syntax error : ']'

Also, this is my second C++ code so I'm kind of a no0b :P So please don't overload me with too much tech talk xP

[Bazzy]

Pass arrays just as anything else identical(a, b, n);

[boredToDeath]

Well I tried doing that, but I get an error :/

...program 3.cpp(20) : error C2664: 'identical' : cannot convert parameter 1 from 'int [99]' to 'int'

Maybe my code is missing a library or something??

[seye]

Do what bazzy says, plus change your function prototype at the top to include square brackets. Also, you should change main to return int.

[boredToDeath]

It worked! I added square brackets to the prototype and it worked, but I didn't need to change the main to return int.

Thanks guys :) :)