Trying to passing 2 parameters using 1 function call as the parameters

[mlwhiteley]

Hi,

I am trying to call a function that needs two parameters. I know I can do something like this:

add(num(),num());

Where add is a function that needs two parameters and I call the num function twice as those parameters. But can I do something like this:

add(num());

Where add still needs two parameters and the function num returns two like maybe:

int num()
{
   int a = 1, b=1;
   return a, b;
}

Thanks for all the help!

[PanGalactic]

No, you cannot return multiple values from a function. But you you can do this:

#include <iostream>

typedef int(*num_type)();

int num() { return 1; }

int add(num_type func) {return func() + func();}

int main()
{
    std::cout << add(num) << std::endl;
    return 0;
}

This passes the function num() to add(), which then calls num() twice.

[mlwhiteley]

Thanks!