Should this work??

[joro550]

I really don't know, but it works on my compiler and gives me this output:

012

#include <iostream>
using namespace std;

class baseClass
{
public:
	baseClass()
	{
	}
	int GiveMe()
	{
		return 0;
	}
};

class derivedClass : public baseClass
{
public:
	derivedClass()
	{
	}
	virtual int GiveMe()
	{
		return 1;
	}
};

class bob : public derivedClass
{
public:
	bob()
	{
	}
	int GiveMe()
	{
		return 2;
	}
};

int main()
{
	baseClass base;
	derivedClass derived;

	bob Mar;
	

	cout << base.GiveMe();
	cout << derived.GiveMe();
	cout << Mar.GiveMe();
	cin.get();

}

[filipe]

Yes, it should, but the virtual keyword is not necessary because you're not using pointers to the base class to enable polymorphism. If those three objects were being accessed through pointers to baseClass, then baseClass' GiveMe() would have to be virtual for that to work. Once a method is declared virtual, it will be virtual for every class that inherits from its own class.