Define namespace::operator<< in chained expression

[Saph]

Hi,
Im trying to figure out a smoother way to solve this problem:

cout << "Value of enum: ";
My_namespace::operator<<(cout, d);
cout << '\n';

The code is working fine but it looks messy.

Is there any way to do this in a chained expression like the following:

cout << "Value of enum: " << My_namespace::<< d << cout << '\n';

Is there any way to assign different namespaces for operators (like operator<<) in a chained expression.

Thanks in advance, and I'm sorry if my poor language skill is shining through.

[jsmith]

You shouldn't need to do that. Koenig lookup will handle the case where operator<< for type T will be found in the
namespace where T is defined without the need for explicit scoping. In other words,

namespace foo {
    struct bar {};

    std::ostream& operator<<( std::ostream&, const bar& ) { /* ... */ }
}

int main() {
    foo::bar b;
    std::cout << b << std::endl; // This should compile
}

[Saph]

You are right, the code compiles fine now. Thanks for clearing that out! And thanks alot for the effort.