If equal don't do anything

[Nuc]

Okay, so I were updating my mini-rpg console app. thingy and I wanted the console to write "Draw!" if both heroes lose (their health below 0)

So how do it? Something like:

if (herohealth >= 0 and villianhealth >= 0) 
cout << "Draw!";

Now, how do I do it correctly?

Also, if I'd want to make something like that:

if (heroname >= 15 or == 30) 
and so on;

Now, how do I do it correctly?

[Moschops]

By using the correct C++ operators. They're all here:

http://www.cplusplus.com/doc/tutorial/operators/

The ones you want are && and ||

[Bazzy]

and and or are valid C++ operator ( as well as && and || )

[Moschops]

True, although they are considered to be the alternative rather than the primary.

[zb0S216C]

@Moschops
As Bazzy said, they're still valid. It's like saying:

#define BEGIN {   // Doesn't change the way '{' operates.
#define END }     // Doesn't change the way '}' operates.

void Function( void )
BEGIN
    // ...
END

[ne555]

I wonder why they are not highlighted here.

//if (heroname >= 15 or == 30) 
if (heroname >= 15 or heroname == 30) 

if (herohealth >= 0 and villianhealth >= 0) //they are still alive 

[firedraco]

Because they are basically macros AFAIK.

[quirkyusername]

they can't be standard, are they in a certain header? I get undeclared identifier errors when I try that.

[ne555]

http://www.cppreference.com/wiki/language/operator_alternative
They do not expand as macros and vim, gedit, ZinjaI do highlight them.

Edit: ZinjaI only highlights and or not xor

[Bazzy]

firedraco wrote:

Because they are basically macros AFAIK.

quirkyusername wrote:

they can't be standard, are they in a certain header? I get undeclared identifier errors when I try that.

In C++ they are standard operators ( not macros ) see [lex.operators] in the ISO document.
In C they are standard macros defined in iso646.h http://www.cplusplus.com/reference/clibrary/ciso646/

[Nuc]

if (mhr >= 0)
	cout << monster << " won the fight!\n";
		else cout << heroname << " won the fight!\n";

if (mhr >= 0 && hhr >= 0)
	cout << "Draw!\n";

Now, how do I make the program not print both "Monster won the fight" and "Hero won the fight" if the fight ends in a draw?

[ne555]

Your condition is upside-down. You should test if both are negative

if( both_negative ) 
  cout << "Draw";
else if( monster_negative ) 
  cout << "Hero wins";
else 
  cout << "Monster wins. Great!";

[Nuc]

monster_negative, what do you mean? I'm supposed to make it a variable?

[ne555]

that was pseudo code. Check if the monster hp is below 0.

[moorecm]

Bazzy wrote:

In C++ they are standard operators ( not macros ) see [lex.operators] in the ISO document.

Has anyone tried overloading "operator and()"? Does it compile? If so, is it independent of operator &&()?

[Bazzy]

They should produce the same token.
This compiles and prints "ok" using g++ 4.5.2

#include <iostream>

struct S
{
    void operator and ( S )
    {
        std::cout << "ok" << std::endl;
    }
};

int main()
{
    S a,b;
    a && b;
}

(edit) should work as well in an implementation where and is a macro as long as that macro is defined and expands to &&

[moorecm]

Interesting. For the macro version, I would expect the spaces before and after "and" in "operator and (" to be required.

[Bazzy]

BTW, using g++ this #define and && will give the following error: "and" cannot be used as a macro name as it is an operator in C++

[Nuc]

if (mhr >= 0 && hhr >= 0)
	cout << "Draw!\n";
		else if (mhr >= 0)
			cout << heroname << " wins!";
		else cout << monster <<" wins!";

If both hero's and monster health is below 0 (if equal 0 it's okay) it says the monster won.

[Johnnyboy]

@Nuc

I think your arrows are pointing the wrong way, your code specifies the condition greater than or equal to. Do you mean less than or equal to?

<=