Get out from nested for loops

[airerdem]

Hi,

for(i=0;i<10;i++)
{
   for(j=0;j<10;j++)
   {
       if()
       {
       Now I want to exit from j loop and continue from i loop.
       }
       And now if it is wrong I want to continue from j loop.
   }
}

Actually I tried break in if statement but it did not help.

[anonymouscoder6]

Have you read about keyword continue? if you want to break from inner loop only and move on to i, use continue statment and if you want t and if its wrong and you want to continue from j loop only, do nothing and let the control flow.

for(i=0;i<10;i++)
{
   for(j=0;j<10;j++)
   {
       if()
       {
       continue; //it will skip rest of the cycles j loop and will take control to i loop.
       }
       // do nothinh here and let the control flow normally since you want to continue from j loop only
   }
}

Makes sense?

[airerdem]

in your example only inner loop (j loop) is affected by continue.

I do not want to enter the j loop second time. After first time just continue from next i.

So, continue increases to next j but I want to exit.

[anonymouscoder6]

You tried break?

[Return 0]

airerdem, you should post your usage of break, it should of worked. Here is an example:

	for ( int i = 0; i < 10; i++ )
	{
		cout << "In i loop " << i << endl;
		for ( int j = 0; j < 10; j++ )
		{
			cout << "In j loop " << j << endl;
			if ( j == 6 )   // or whatever condition, if the condition is false, the j loop continues
				break; // break out of j loop
		}
	}

[airerdem]

for(i)
{
	for(j)
		{
			if ()
			{
					for()
					{
					something
					}
				break;
			}
		}
}

actually it worked one time in j loop and stopped. (Didn't pass second i value)

[anonymouscoder6]

sorry, your question is not clear.

[airerdem]

for(i=0;i<10;i++)
{
	for(j=0;j<10;j++)
		{
			if (a>b)
			{
                        cout << "a>b";
					for(k=0;k<10;k++)
					{
					cout <<k;
					}
		        break;
			}
		}
}

I mean if a>b then I want to stop j cycle (after cout k values) and increase i. If it is not I want to increase j until a>b. But in this code it just enters the both loop one time and program stops !

[anonymouscoder6]

1. Where are the values of a and b changing. I dont see it anywhere. So loop will function the same way every time.
2. If you want to break after cout<<k; and stop j cycle, use break twice, once in k loop and another one in j loop after k loop, like this:

for(i=0;i<10;i++)
{
	for(j=0;j<10;j++)
		{
			if (a>b)
			{
                        cout << "a>b";
					for(k=0;k<10;k++)
					{
					cout <<k;
                                        if (a>b)
                                        break;
					}
		        if (a>b)
                        break;
			}
		}
}

sidenote: I am quite curious to know what exactly are you trying to achieve with this code, which, imo, is doing nothing.

[airerdem]

1. a and b are just example I want to know the logic.

2. in this time only first value of k will be printed, but I want to stop after all k values are printed.

and I appreciate your help ;)

[anonymouscoder6]

try this:

for(i=0;i<10;i++)
{
	for(j=0;j<10;j++)
		{
			if (a>b)
			{
                        cout << "a>b";
					for(k=0;k<10;k++)
					{
					cout <<k;
                                        }
		        if (a>b)
                        break;
			}
		}
}

Let me know if it works and also if it does not work. :P

[moorecm]

I would expect break to work. Perhaps execution is not reaching the statement.

Alternatively, dare I say that nested breaking might be a fair case to consider using goto. Assuming that break doesn't fit your needs and adding flags at each scope is not practical.

[airerdem]

ok the problem is solved as anonymouscoder6 explained.

thank you

[anonymouscoder6]

Congrats Airedem. :)