error on a simple program

[shazlin]

The problem is when i entered letters the program keep saying
"Invaild number entered--Try again: ""Enter a double number: "
it just wont let me cin the number[count];

const int SIZE =20;
double* number = new double[SIZE];
int count = 0;
do {
cout << "Enter a double number: ";
cin >> number[count];

while (!cin.good() && !cin.eof()) {
cout << "Invaild number entered--Try again: ";
cin >> number[count];
system("PAUSE");
}
}while(!cin.eof());

Thank You

[andrezc]

Do you wanna only numbers in your program and ignore the letters? if yes, you can ignore strings data type in your program with the scanf() function. For example:

scanf("%[A-Z]s", str);

in this code, I ignore any char of A at Z.

----------------------
Sorry any english error, I from Brazil.

[packetpirate]

Can I ask why you're trying to enter letters in a double array?

[shazlin]

Ty. andrezc i never used scanf before, but i tried those scanf in my program. so what if a user entered a string instead of letters.

for Packetpriate, in this program i need to test for invaild number. for instance, if user entered a letter or a string, i should let user enter the number again.

I just dont get it why it doesnt go to if statement of cin.

Thank You guys

[wolfgang]

Oh. Well if your trying to avoid a cin>> error when user enter non number chars you should be using this:

while ( !std::cin )
{
  std::cin.clear()
  std::cin.ignore( std::numeric_limits< std::streamsize >::max(), '\n');
  std::cout << "Invalid Number. Please Retry: "; std::cin >> number[count];
}

EDIT: You'll need to #include <limits> for this code.

[andrezc]

Ty. andrezc i never used scanf before, but i tried those scanf in my program. so what if a user entered a string instead of letters.

Oh, sorry. You using C++... :D

[shazlin]

Ty guys
Long time didn't touch to c++, always working on java and almost forgot how to write it ;p