pointer to function

[theimmortalbg]

hello this is my program

#include "stdafx.h"
#include <iostream>
using namespace std;

bool isOdd(const int* item)
{
return (*item)%2;
}

int deleteItems (int *array, int itemSize, int itemsCount, bool (*shouldDeleteItem)(const int*))
{
for(int i=0; i<itemsCount; i++)
cout<< shouldDeleteItem (array+i)<< endl;

return itemsCount*itemSize;
}

void main()
{
int *p = NULL;
int n;
cout<< "Enter length of array: ";
cin>> n;
p = new int [n];

cout<< "Numbers in the array: ";
for(int i=0; i<n; i++)
cin>> *(p+i);

for(int i=0; i<n; i++)
{
deleteItems(p, sizeof(p+i), n, isOdd(p+i));
}
}

I am trying to call the function deleteItems(int *array, int itemSize, int itemsCount, bool (*shouldDeleteItem)(const int*)) but i can't. Compiler says cannot convert parameter 4 from bool to bool(_cdecl*)(const int *). How i can call delleteItems with last parameter isOdd(p+i). Thanks

[quirkyusername]

deleteItems() 4th parameter is a pointer to a function which returns a bool and takes one const int parameter, but what you are passing it is the result of a call to isBool() which returns a bool, not a pointer to a function

[coder777]

This deleteItems(p, sizeof(p+i), n, isOdd(p+i)); must be deleteItems(p, sizeof(p+i), n, isOdd);. That removes the compiler error. Are you aware that sizeof(p+i) is always the pointer size (in 32 bit systems = 4). But I see that you don't need it at all.

[theimmortalbg]

thank u guys realy appreciate !

[chipp]

deleteItems() 4th parameter is a pointer to a function which returns a bool and takes one const int parameter, but what you are passing it is the result of a call to isBool() which returns a bool, not a pointer to a function

i don't understand, why you said that that is the call to isBool() ? i don't see any of that function declaration before. or is it on the library?

[quirkyusername]

sorry I meant IsOdd