Unknown parameter in array

[Krahl]

Hi,

I am using an array of type integer as an argument in a function,

e.g. void Function(iaaArray[][45]){}

What I would like to do is have something like...

void Function(iaaArray[][iInt]){}

where iInt is an integer determined by the user.

So I can allow for different sized arrays to be passed into the function.

Can someone help me with this.

Thanks Krahl

[firedraco]

Take the array as a pointer and pass the size separately:

void func(int* array, unsigned int size)

[Krahl]

thanks for the reply firedraco.

I have tried and it doesn't seem to accept it.

This is a simplified version of what I'm doing...

#include <iostream>

void func(int* piaaArray, unsigned int uiSize, unsigned int uiLength){
    for (int j = 0; j < uiLength; j++){
        for (int i = 0; i < uiSize; i++){
            std::cout << *piaaArray[j][i];
        }
    }
}

int main(){

int* piaaArray[5][8];

func(piaaArray, 5, 8);

return 0;

}

and when I place as argument iaaArray[][] it seems to insist on the size of the multidimensional array. I could easily just define the array to be a ridiculous size like iaaArray[900][900] because I know it won't ever need to be bigger than that but I'd prefer not to do that.

[Browni3141]

I'm pretty sure my compiler allows what the OP is asking for. Is that non-standard?
If it doesn't work with arrays it should work with vectors.

[Krahl]

well anyway, what I actually ended up doing is creating my own 2 dimensional array in a 1 dimensional array since it's basically the same as a 2 dimensional array, you just need to be more careful where the next row comes in.

I am still interested in a solution to this though.

So Browni3141, your compiler allows for my code snippet?

[ne555]

That is a good solution.
You could also generate all overload functions with every possible number in columns (templates)

template<unsigned int cols>
void foo(int array[][cols],unsigned int rows);

[Krahl]

Hey thanks ne555 I forgot I could use template functions.