How do I do this?

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b***h?

Well since they're constant I didn't think it was SOO bad but, like I said up there somewhere, I make a 2d array of pointers based on the size of the screen. So they need to be constant. (Well I don't use new cuz then they wouldn't need to be, eh, they would still need to be constant to pass the 2d array to a function, unless there is a different way to do that, that I haven't found)
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THIS JUST IN:
How to create arrays of variable size and pass them to functions:
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void f(int *arr,int size){
	//???
}

int main(){
	int x=rand(); //I'm feeling wacko.
	int *arr=new int[x];
	f(arr,x);
	return 0;
}
2d arrays? Ideas?

I know what your saying, I'm just stuck
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That's a bit trickier. Well, more like an escalation:
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void f(int **arr,int sizex,int sizey){
	//???
}

int main(){
	int x=rand(); //I'm feeling wacko.
	int y=rand();
	int **arr=new int*[x];
	for (int a=0;a<x;a++)
		arr[a]=new int[y];
	f(arr,x,y);
	return 0;
}

Naturally, you address elements with arr[x<sizex][y<sizey].
A thing about matrices: IIRC, their physical (well, in this case the physical representation will be different. This is more of a conceptual representation) representation is
[0][0];[0][1];[0][2]; [1][0];[1][1];[1][2]; [2][0];[2][1];[2][2];
I'm still not too great with the whole pointer thing. If this makes it any worse than whats above, its a 2d array of pointers to objects =P What's so wrong with global constants anyways?
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Boy, are you trying to give me an aneurysm? Haha.
If you need a matrix of pointers to objects just find and replace all instances of int (where it refers to arr! Don't try to assign a random number to a pointer, now) with name_of_class *.
Don't forget the function signature or you'll get a horribly confusing compiler error.
Huh. You've just made me use a *** for the first time.
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Lol, I appreciate the help, you don't need to show me how to do the *** thing, I'll figure that out once I play with simpler ones. I'll play with that in the morning, it's just a bit late now.

Thanks again for the help.
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