sorting problem

[noobie]

hello..
i have kined of noobie question..
if i have a string : "a,f,b,k,e"
and i want to convert it, so it will look like this : "e,k,b,f,a".
how can i do it??
(i think i have to move them to the right or left 5 times).
Basically i need to create a program that get an arry from the user and it shouldnt be more that 50 chars.
then do what i showed you above.
i tryed to make an other arry and do like this:

#include <iostream>
using namespace std;
int main ()
{
int i,j,a;
char one[a],two[a];// dont shore this is correct.
do
{
cout<<"enter char less than 50.\n";
cin>>one[a];
}
while (a>50);
// i dont know how to set the valu of "a" ! 
// it should be the number of the chars in the arry.
// depends on what the user enter.
for (j=0;j<a;j++)
{
    for (i=0;i<a;i++)
    {
        two[i+1]=one[i];
    }
two[0]=one[a];
}
cout<<"now you got "<<two[a]<<endl;
system ("PAUSE");
return 0;
}

but it didn't work.
hlp me pls :)

~~~~~~~~~~~~~~~~~~~~~
Edit : ohhh i got a terible mistake! i cant do this by moving them 50 times to the right cuz its geting back to where it starts..
so i still need your help.. :D

[shredded]

Hi

I think you might be after something like what follows.

I assume that you want to reverse the string thats inputed and not the commas.

#include <iostream>
#include <string.h>

using	namespace	std;

int	main(int argc,char** argv)
{
	char	one[50];			//reserve space for 50 characteers
	char	two[50];			//

	cout << "enter less than 50 characters" << endl;

	cin >> one;				// all characters go into character array.

	int	length = strlen(one);		//length in Characters

	for (int i=0;i<length;i++)	
	{	
		two[length-i-1] = one[i];	 //Reverses Order
	}

	cout << "now you got " << two << endl; //output result
}

Hopefully this is a good example of what you wanted.
Shredded

[noobie]

thank you shredded.
but i think you use pointers..
and i want to solve this without pointers and strlen.
i'm still at the begining.

is there any option to do so?
thanks!

[shredded]

hi again,

Im not sure you can do without pointers of some type.

char one[50] is a pointer to an array of 50 characters.

You can get by without using strlen by doing something like this

    int     length = 0;

    while (one[length] != 0)        // 0 terminates character string
    {
          length++;
    }

Sorry I couldn't help more
Shredded

[noobie]

thank you alot!!!