3 x 3 array

[hunkeelin]

Write a program that tests whether a 3 x 3 array, which you may hard code, is a magic square. A magic square is an N x N matrix of numbers in which every number from 1 to N*N must appear just once, and every row, column, and diagonal must add up to the same total.

So this is what i do.
#include <iostream>

#include <math.h>

#include <string>

using namespace std;





char quit;



int main( )

{

//declaring the 2d matrix arrays



float matrix1[3][3];

float matrix2[3][3];





cout << "Week 5 Assignment, A-5B of two 2d 3x3 matrixes by DR. " <<endl;



//*************assigning numbers to the first matrix*********

for (int row = 0; row < 3; row++)

for (int column = 0; column < 3; column++)

{

cout << "Enter value for row " <<row+1 << " column " <<column+1 << ": " << endl;

cin >> matrix1[row][column];

}



int row, column;



for (row = 0; row < 3; row++)

{

for (column = 0; column < 3; column++)

cout << matrix1[row][column];

cout << endl;

}

“this is what I am missing, I don’t know how to locate each the number. I want to write a if loop that do the following.

If

row 11 + row 12 + row 13 = 15

row 22 + row 21 + row 23 = 15

until I tried all write every row every column and diagonally it adds to 15.

A if loop that make sure row 11 isn’t equal any of the other number and do it for the other 8 numbers in the magic square.

Lastly if the condition from above are satisfy, cout<<” it is a magic square”;

Else

Cout << “it is not a magic square”;



}


Some how i can't complete it.