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Declare of function default value

force123 (6)
Hello,

This is a simple question, however I can't find the answer on the net.

I have this code:

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#include <iostream>
using namespace std;

void myFunc(int x = 3)
{
    cout << x << endl;
}

int main()
{
    myFunc();

    return 0;
}


which works fine. Now I want to declare the function on top so that I move the function definition to the bottom of the code:

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#include <iostream>
using namespace std;

void myFunc(int x);

int main()
{
    myFunc();

    return 0;
}

void myFunc(int x = 3)
{
    cout << x << endl;
}


Because of the default value, my compiler doesn't accept it. I tried many syntaxes, all failed. Any idea?
Bazzy (6281)
On line 8 the default value is not visible ( because you expressed it on line 13 )
This is the correct way:

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void myFunc(int x = 3);

int main()
{
    myFunc();

    return 0;
}

void myFunc(int x)
{
    cout << x << endl;
}
force123 (6)
ah the closest try I had was to put (int x = 3) for both declare and definition.
Thanks a lot! :)
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