C++ simple question

[qwertyasdfgh]

replace this do-while loop with a while loop. When u do this you will no longer need an if statement.

cout << "Enter an even number: ";
do
{ cin >> number;
if (number % 2 !=0)
cout << "Number must be even. Reenter number: ";
} while (number % 2 !=0);



THANKS--

[hamsterman]

try.

[qwertyasdfgh]

i did try many times bro it doesn't work

[qwertyasdfgh]

i did try many times bro it doesn't work

[filipe]

Where's the code that "doesn't work"?

[qwertyasdfgh]

cout << "Enter an even number: ";
do
{ cin >> number;
if (number % 2 !=0)
cout << "Number must be even. Reenter number: ";
} while (number % 2 !=0);

[filipe]

You didn't replace the do-while with a while loop.

[qwertyasdfgh]

i know that is why im asking you to do it because when i tried it doesn't work

[filipe]

We need to see the code you wrote that doesn't work so we can help you fix it. If you post it, we can help you make it work.

[Browni3141]

This is the syntax for a while loop:

while (condition)
{
     // code
}

I don't understand what you can't figure out.

[qwertyasdfgh]

please answer it i dun hv time

[Browni3141]

Apparently you dun hv time to spell out your words either. The only way I could make it simpler is by giving you the answer.

[Edit]: Give it your best attempt and post it.

[qwertyasdfgh]

then tell me

[qwertyasdfgh]

#include <iostream>
using namespace std;

int main()
{
	int number;
		cout << "Enter an even number: ";
		while (number % 2 != 0);
		{	cin >> number;
		
			cout << "Number must be even. Reenter number: "; }
return 0;
}

here is the code now answer

[Browni3141]

This is very close. Add cin >> number; between lines 8 and 9, and switch lines 10 and 12.

[hamsterman]

problem 1. ';' after while(). That just creates an empty loop.
problem 2. comparison happens before input. One way would be to have cin >> number once before the loop and once in it (after cout << ... ). Another one would be while(cin >> number && number %2 != 0){...