I'm getting a small output error. Assistance needed!

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/* 
This program will find the roots of one of three different functions on one of 
two intervals based on user input.
*/

#include <stdio.h>
#include <math.h>
#include <stdlib.h>


double evaluate(double f(double), double a, double b, double error) {
	double mid;
	double f_mid;
	double f_a = f(a);
	double f_b = f(b);
	

	while(fabs(a- b) > error) {
		
		mid = (a+b)/2.0;

		f_mid = f(mid);		

			if(f_mid == 0.0)
        	{
			break;
			}
        
			else if((f_mid * f_a) < 0.0)
        	{
			b = mid;
			}
			
			else
			{
			a = mid;
        	}
    	}
if (fabs(a-b) == error)
	printf("No root found.");
	
	return mid;
}

double func1(double x) {
	return (3.0*x*x*x) - (3.0*x*x) + 0.2;
}

double func2(double x) {
	return (x*x*x*x) - (3.0*x*x) - 8.0;
}

double func3(double x) {
	return 2.0*sin(2.0*x) - 3.0*cos(3.0*x);
}

int main(void)

{
int o, p;

double a, b, error, root, root_value;



	printf("Which function do you want to choose (1,2,3): ");
error1:
        scanf("%d", &o);

switch ( o ) {

case 1:

     printf("Which interval do you want to choose (1,2): ");
error2:
     scanf("%d", &p);

     printf("What error is accepted (epsilon): ");
     scanf("%g", &error);

	switch ( p ) {
	
	case 1:
		a = -1.0;
		b = 0.0;

        root = evaluate(func1, a, b, error);
		
	root_value = func1(root);

		printf("The root of the function 1 in the interval 1 is %g.\nThe function value at the root is %g\n", root, root_value);
		break;

	case 2: 
		a = 0.0;
        	b = 0.5;

	root = evaluate(func1, a, b, error);
              
        root_value = func1(root);

		printf("The root of the function 1 in the interval 2 is %g.\nThe function value at the root is %g\n", root, root_value);
                break;

	default:
	       printf("ERROR: Enter 1 or 2 for your interval: ");
                goto error2;
                break;
	}

     break;

case 2:
 
     printf("Which interval do you want to choose (1,2): ");
error3:
     scanf("%d", &p);

     printf("What error is accepted (epsilon): ");
     scanf("%g", &error);

	switch ( p ) {

        case 1:
                a = -4.0;
                b = -2.0;

		root = evaluate(func2, a, b, error);
                root_value = func1(root);

		printf("The root of the function 2 in the interval 1 is %g.\nThe function value at the root is %g\n", root, root_value);
                break;

        case 2:
                a = 2.0;
                b = 4.0;

		root = evaluate(func2, a, b, error);
                root_value = func2(root);

 		printf("The root of the function 2 in the interval 2 is %g.\nThe function value at the root is %g\n", root, root_value);
                break;
        default:
                printf("ERROR: Enter 1 or 2 for your interval: ");
                goto error3;
                break;
        }
	break;

case 3:

     printf("Which interval do you want to choose (1,2): ");
error4:
     scanf("%d", &p);
     printf("What error is accepted (epsilon): ");
     scanf("%g", &error);

        switch ( p ) {

        case 1:
                a = 0.0;
                b = 1.0;

		root = evaluate(func3, a, b, error);
                root_value = func3(root);

		printf("The root of the function 3 in the interval 1 is %g.\nThe function value at the root is %g\n", root, root_value);
                break;

        case 2:
                a = 1.0;
                b = 2.0;

		root = evaluate(func3, a, b, error);
                root_value = func3(root);

 		printf("The root of the function 3 in the interval 2 is %g.\nThe function value at the root is %f\n", root, root_value);
                break;
        default:
                printf("ERROR: Enter 1 or 2 for your interval: ");
                goto error4;
                break;
        }
    
     break;

default:
     printf("Enter a number between 1 and 3: ");
     goto error1;
     break;
}

return 0;
}


I am not getting any output for case 2 in switch ( o ) or for case 3 in switch ( o ). Function 1 works fine. I believe there's a problem with my nested switch. Any help is very much appreciated!
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