Why doesn't this work?

[airman9519]

I was making a program that takes a two-dimensional array of chars that can be either '#' or '.' from a text file and makes it work like tetris. '#' are blocks and '.' are empty spaces so if there is a empty space below it moves the block down. This is my program(it's C not C++):

#include <stdio.h>

int main(void)
{
FILE *ifStr;

ifStr = fopen("input.txt", "r");

char ch[5][5];
int x;
int y;

if(!ifStr) return 0;

for(x = 0;x <= 4;x++)
{

    for(y = 0;y <= 4;y++)
    {
     fscanf(ifStr, "%c", &ch[x][y]);
    }
}


int down = 1;
//
do{
down = 1;
for(x = 0;x <= 4;x++)
{
   for(y = 0;y <= 4;y++)
    {

        if(ch[x][y] == '#' && ch[x + 1][y] == '.')
        {
            ch[x][y] = '.';
            ch[x + 1][y] = '#';
            down = 0;
        }
    }
}
}while(down != 1);
//
FILE *ofStr;

ofStr = fopen("output.txt", "w");

if(!ofStr) return 0;

for(x = 0;x <= 4;x++)
{

    for(y = 0;y <= 4;x++)
    {

        fprintf(ofStr, "%c", ch[x][y]);
    }
    fprintf(ofStr, "\n");
}

fclose(ofStr);
fclose(ifStr);
return 0;
}

Don't mind the empty comments.

It just crashes. Why?

[filipe]

From a real quick look, lines 34 and 37 seem to access and write into out of range memory (x + 1 when x is 4).

[airman9519]

I've fixed that. In line 29 I put ;x <= 3; but it still doesn't work. Thanks anyway!

[filipe]

Line 53: for(y = 0;y <= 4;x++)

[airman9519]

Thanks!