Leap Years using while

[jellyfish]

while ((dd == 29 && mm == 2) && ((yr%4 = 0 && yr%100 !=0) || yr%400 == 0))
		{

			cout << "Invalid day" << endl
				 << "Reenter the day: " << endl;
			cin >> dd;

Had check around this forum & using google as well.
Seem there no example on using while statement for leap years.

Is it possible to use while statement for leap years?

[Athar]

Well, of course... you just confused = with ==.

[jellyfish]

Hi Athar,

while ((dd == 29 && mm == 2) && ((yr%4 == 0 && yr%100 !=0) || yr%400 == 0))
		{

			cout << "Invalid day" << endl
				 << "Reenter the day: " << endl;
			cin >> dd;
		}

Year 2000 is a leap year but 1800 is not. If using above code, it will treat 1800 as leap year 2000 as non-leap year.

[Disch]

In order to make this sane, you should put that complicated mess of comparisons in a separate function:

bool IsDateValid(int m,int d,int y)
{
   // return true if valid date
   // return false otherwise
}

//...

   while( !IsDateValid(mm,dd,yr) )
   {
     //...
   }