hello i have a problem with getline function on structure * pointer

[p00nani]

hello i have a problem i used an structure to make a database
of movies that the user sow i came from the tutorial on the site
i just made it to interact with a user

// array of structures//
#include <iostream>
#include <string>
#include <sstream>

using namespace std;

struct movies_t {
  string title;
  int year;
};

void printmovie (movies_t movie);

movies_t * pointer;


int main ()
{
  string mystr;
  int n,size;
  
  cout <<"enter how mov"; //the amount of movies you want to enter//
  cin >> size;
  pointer = new movies_t [size];  
  for (n=0; n<size; n++)
  {
    cout << "Enter title: ";
    cin >> pointer[n].title; /*if i use the getline (cin,pointer[n].title) 
    my program skip the cout << "enter title and the 
    getline (cin,pointer[n].title and goes to the cout << enter year*/
    cout << "Enter year: ";
    cin >> pointer[n].year;
    
  }

  cout << "\nYou have entered these movies:\n";
  for (n=0; n<size; n++)
    printmovie (pointer[n]);

    cin >> size;
  return 0;
}

void printmovie (movies_t movie)
{
  cout << movie.title;
  cout << " (" << movie.year << ")\n";
}

please help me

best regards,
Evgeny Bershadski

[hamsterman]

This happens because cin >> leaves the newline char in the input stream. Then getline finds that newline and therefore an empty string is read. To prevent this, use cin.ignore() after cin >>. cin.ignore discards a number of chars in the stream until a delimiter is found. The arguments you should use are cin.ignore(numeric_limits<streamsize>::max(), '\n');

[p00nani]

thanks but i didnt learned it yet so i have no clue about the cin.ignore(numeric_limits<streamsize>::max(), '\n');

im still at data structures and havent seen it yet in the tutorial in this site

[hamsterman]

well, if you don't like cin.ignore(), you could use cin.get().. or you could add an additional getline after every cin >>..