Incorporating a Password Attempt Limit

[nightrun]

Hi folks, i'm new to C++ (as my code will prove obvious)

Let me start out by saying i've searched both google and these forums to no avail...

I'm fresh out of ideas how to incorporate a password attempt limit to my program... my goal is to have my "getPassword" subprogram tell "main" weather or not 3 tries have occurred, and if so...weather to proceed executing the program or not. Here's what i have so far, clearly something is wrong (getting compiling errors) -- anyone have a hint for me?

#include <fstream>
#include <iomanip>
#include <iostream>
#include <string>
using namespace std;
#include <cmath>

int getPassword()
{
  int result; // attempts
  string password;
  for (result = 0; result < 3; result++)
  {
    cout << "Enter the TOP SECRET passcode: ";
    getline(cin, password);
  
    if (password == "1273296") break;
    cout << "INVALID. ";
  } // for
  return result;
} // getPassword


int main()
{
  int getPassword();  
  if (getPassword() > 1) break;

  cout << "This program was built to..." << endl << endl; 

  double p;
  cout << "What's the Mortgage Amount? ";
  cin >> p;
  cin.ignore(1000, 10); 
  
  double interest;
  cout << "What's the Annual Interest Rate? ";
  cin >> interest;
  cin.ignore(1000, 10);
  
  double i = interest / 100;
  double r = i / 12;
  double n = 360;
  double M = ((p * pow(1 + r, n) * r) / (pow(1 + r, n) - 1));
  
  cout << endl;
  cout << fixed;
  cout << setprecision (0);
  cout << "Mortgage Amount = $" << p << endl;

  cout << setprecision (3);
  cout << "Annual Interest Rate = " << interest << "%" << endl;

  cout << setprecision (0);
  cout << "Amortization Period = " << n / 12 << " Years" << endl;

  cout << setprecision (2);
  cout << "The monthly payment will be $" << M << endl;

  ofstream fout;
  fout.open("mortgages.txt", ios::app);
  if (!fout.good()) throw "I/O error";
  fout << "For A loan Amount of $" << p << ", at an interest rate of " << interest << "%, the monthly payment is $" << M << endl;
  fout.close();

  return 0;
}

[Null]

The code looks good except the break statement in line 27. Write return 0; instead of break so the program will quit

You can also rewrite getPassword function that it will return false if user inputed password incorrectly for 3 times:

bool getPassword()
{
  int result; // attempts
  string password;
  for (result = 0; result < 3; result++)
  {
    cout << "Enter the TOP SECRET passcode: ";
    getline(cin, password);

    if (password == "1273296") break;
    cout << "INVALID. ";
  } // for
  if(result>2)
      return false;  // return false if password was invalid for 3 times
  else return true;
} // getPassword 

and in main you can write
if (!getPassword()) return 0;

[nightrun]

thanks for the quick reply -- this is exactly what i was looking for!